Advertisements
Advertisements
Question
Give reactions for the following:
O – O single bond is weaker than S – S single bond.
Advertisements
Solution
Due to smaller size of ‘O’ as compared to ‘S’. Smaller size of O leads to smaller O–O bond length. As a result, the lone pair of electrons on the both O atoms repel each other leading to instability or weakening of O–O bond. S is relatively larger so an repulsion between lone pair electrons.
APPEARS IN
RELATED QUESTIONS
Give reasons for the following : H2Te is the strongest reducing agent amongst all the hydrides of Group 16 elements.
Justify the placement of O, S, Se, Te and Po in the same group of the periodic table in terms of electronic configuration, oxidation state and hydride formation.
Knowing the electron gain enthalpy values for \[\ce{O -> O-}\] and \[\ce{O -> O^{2-}}\] as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O−?
(Hint: Consider lattice energy factor in the formation of compounds).
Explain the following properties of group 16 elements :
1) Electro negativity
2) Melting and boiling points
3) Metallic character
4) Allotropy
The boiling points of hydrides of group 16 are in the order:
The formation of \[\ce{O^+_2[PtF6]^-}\] is the basis for the formation of first xenon compound. This is because ____________.
Out of \[\ce{H2O}\] and \[\ce{H2S}\], which one has higher bond angle and why?
In forming (i) \[\ce{N2 -> N^{+}2}\] and (ii) \[\ce{O2 -> O^{+}2}\]; the electrons respectively are removed from:
The correct order of ΔiHs among the following elements is
______ is a radioactive element in group 16 elements.
