English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Match the items of Columns I and II and mark the correct option. Column I Column II (A) HX2SOX4 (1) Highest electron gain enthalpy (B) CClX3NOX2 (2) Chalcogen (C) ClX2 (3) Tear gas (D) Sulphur (4) - Chemistry

Advertisements
Advertisements

Question

Match the items of Columns I and II and mark the correct option.

Column I Column II
(A) \[\ce{H2SO4}\] (1) Highest electron gain enthalpy
(B) \[\ce{CCl3NO2}\] (2) Chalcogen
(C) \[\ce{Cl2}\] (3) Tear gas
(D) Sulphur (4) Storage batteries

Options

  • A - (4), B - (3), C - (1), D - (2)

  • A - (3), B - (4), C - (1), D - (2)

  • A - (4), B - (1), C - (2), D - (3)

  • A - (2), B - (1), C - (3), D - (4)

MCQ
Advertisements

Solution

A - (4), B - (3), C - (1), D - (2)

Explanation:

Column I Column II
(A) \[\ce{H2SO4}\] (4) Storage batteries
(B) \[\ce{CCl3NO2}\] (3) Tear gas
(C) \[\ce{Cl2}\] (1) Highest electron gain enthalpy
(D) Sulphur (2) Chalcogen
shaalaa.com
  Is there an error in this question or solution?
Chapter 7: The p-block Elements - Multiple Choice Questions (Type - I) [Page 98]

APPEARS IN

NCERT Exemplar Chemistry [English] Class 12
Chapter 7 The p-block Elements
Multiple Choice Questions (Type - I) | Q 61 | Page 98

RELATED QUESTIONS

Account for the following: Oxygen shows catenation behavior less than sulphur.


a. Explain the trends in the following properties with reference to group 16:

1 Atomic radii and ionic radii

2 Density

3 ionisation enthalpy

4 Electronegativity

b. In the electolysis of AgNO3 solution 0.7g of Ag is deposited after a certain period of time. Calulate the quantity of electricity required in coulomb. (Molar mass of Ag is 107.9g mol-1)

 


List the important sources of sulphur.


Write the order of thermal stability of the hydrides of Group 16 elements.


Why does NH3 form hydrogen bond but PH3 does not?


Justify the placement of O, S, Se, Te and Po in the same group of the periodic table in terms of electronic configuration, oxidation state and hydride formation.


Knowing the electron gain enthalpy values for \[\ce{O -> O-}\] and \[\ce{O -> O^{2-}}\] as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O?

(Hint: Consider lattice energy factor in the formation of compounds).


Why are halogens strong oxidising agents?


Arrange the following in the order of property indicated for the given set:

F2, Cl2, Br2, I2 - increasing bond dissociation enthalpy.


Give a reason for the following:

Fluorine gives only one oxide but chlorine gives a series of oxides.


Arrange the following in order of the property indicated set.
HF, HCl, HBr, HI - decreasing bond enthalpy.


Given below are two statements labelled as Assertion (A) and Reason (R).

Assertion (A): Electron gain enthalpy of oxygen is less than that of Flourine but greater than Nitrogen.

Reason (R): Ionisation enthalpies of the elements follow the order Nitrogen > Oxygen > Fluorine.

Select the most appropriate answer from the options given below:


Strong reducing behaviour of \[\ce{H3PO2}\] is due to ______.


Which of the following statements are correct?

(i) \[\ce{CaF2 + H2SO4 -> CaSO4 + 2HF}\]

(ii) \[\ce{2HI + H2SO4 -> I2 + SO2 + 2H2O}\]

(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]

(iv) \[\ce{Nacl + H2SO4 -> NaHSO4 + HCl}\]


Out of \[\ce{H2O}\] and \[\ce{H2S}\], which one has higher bond angle and why?


These are physical properties of an elements.

  1. Sublimation enthalpy
  2. Ionisation enthalpy
  3. Hydration enthalpy
  4. Electron gain enthalpy

The total number of above properties that affect the reduction potential is ______. (Integer answer)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×