English

Evaluate the following : ∫sin(logx)2x.log.x.dx

Advertisements
Advertisements

Question

Evaluate the following : `int(sin(logx)^2)/x.log.x.dx`

Sum
Advertisements

Solution

Let I = `int(sin(logx)^2)/x.log.x.dx`

Put (logx)2 = t

∴ `2logx. 1/x.dx` = dt

∴ `1/xlogx.dx = (1)/(2)dt`

∴ I = `(1)/(2) int sin t.dt`

= `-(1)/(2) cost + c`

= `-(1)/(2)cos[(logx)^2] + c`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Exercise 3.3 [Page 137]

APPEARS IN

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Evaluate `int_0^(pi)e^2x.sin(pi/4+x)dx`


Integrate the function in x sin x.


Integrate the function in x log 2x.


Integrate the function in ex (sinx + cosx).


Integrate the function in `e^x (1 + sin x)/(1+cos x)`.


Integrate the function in `((x- 3)e^x)/(x - 1)^3`.


Prove that:

`int sqrt(x^2 + a^2)dx = x/2 sqrt(x^2 + a^2) + a^2/2 log |x + sqrt(x^2 + a^2)| + c`


Evaluate the following : `int x^2.log x.dx`


Evaluate the following : `int (t.sin^-1 t)/sqrt(1 - t^2).dt`


Integrate the following functions w.r.t.x:

`e^-x cos2x`


Integrate the following functions w.r.t. x : `e^x .(1/x - 1/x^2)`


Integrate the following functions w.r.t. x : `[x/(x + 1)^2].e^x`


Integrate the following functions w.r.t. x : `e^x/x [x (logx)^2 + 2 (logx)]`


Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`


Integrate the following functions w.r.t. x : `e^(sin^-1x)*[(x + sqrt(1 - x^2))/sqrt(1 - x^2)]`


Integrate the following functions w.r.t. x : `log(1 + x)^((1 + x)`


Choose the correct options from the given alternatives :

`int cos -(3)/(7)x*sin -(11)/(7)x*dx` =


Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`


Integrate the following w.r.t.x : `(1)/(x^3 sqrt(x^2 - 1)`


Solve the following differential equation.

(x2 − yx2 ) dy + (y2 + xy2) dx = 0


Evaluate: `int "dx"/(3 - 2"x" - "x"^2)`


Evaluate: `int e^x/sqrt(e^(2x) + 4e^x + 13)` dx


Evaluate:

∫ (log x)2 dx


`int ("e"^xlog(sin"e"^x))/(tan"e"^x)  "d"x`


`int sqrt(tanx) + sqrt(cotx)  "d"x`


Choose the correct alternative:

`intx^(2)3^(x^3) "d"x` =


`int"e"^(4x - 3) "d"x` = ______ + c


Evaluate `int 1/(x log x)  "d"x`


`int cot "x".log [log (sin "x")] "dx"` = ____________.


Evaluate the following:

`int (sin^-1 x)/((1 - x)^(3/2)) "d"x`


Evaluate the following:

`int ((cos 5x + cos 4x))/(1 - 2 cos 3x) "d"x`


Evaluate the following:

`int_0^1 x log(1 + 2x)  "d"x`


The value of `int_0^(pi/2) log ((4 + 3 sin x)/(4 + 3 cos x))  dx` is


Find: `int (2x)/((x^2 + 1)(x^2 + 2)) dx`


`int 1/sqrt(x^2 - a^2)dx` = ______.


If `int(x + (cos^-1 3x)^2)/sqrt(1 - 9x^2)dx = 1/α(sqrt(1 - 9x^2) + (cos^-1 3x)^β) + C`, where C is constant of integration , then (α + 3β) is equal to ______.


Find `int e^(cot^-1x) ((1 - x + x^2)/(1 + x^2))dx`.


Solution of the equation `xdy/dx=y log y` is ______


`int(3x^2)/sqrt(1+x^3) dx = sqrt(1+x^3)+c`


Evaluate the following.

`intx^3  e^(x^2) dx`


Evaluate the following.

`intx^3 e^(x^2) dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)  dx`


Evaluate `int(1 + x + x^2/(2!))dx`.


`∫ sin^(−1)` xdx is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×