English

Choose the correct options from the given alternatives : ∫sinmxcosm+2x⋅dx =

Advertisements
Advertisements

Question

Choose the correct options from the given alternatives :

`int (sin^m x)/(cos^(m+2)x)*dx` = 

Options

  • `(tan^(m+1)x)/(m + 1) + c`

  • (m + 2)tanm+1 x + c

  • `tan^mx/m + c`

  • (m + 1)tanm+1 x + c

MCQ
Advertisements

Solution

`(tan^(m+1)x)/(m + 1) + c`

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Miscellaneous Exercise 3 [Page 148]

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Integrate the function in `x^2e^x`.


`intx^2 e^(x^3) dx` equals: 


Prove that:

`int sqrt(x^2 + a^2)dx = x/2 sqrt(x^2 + a^2) + a^2/2 log |x + sqrt(x^2 + a^2)| + c`


Find : 

`∫(log x)^2 dx`


Evaluate the following : `int x^2.log x.dx`


Evaluate the following:

`int x tan^-1 x . dx`


Evaluate the following : `int log(logx)/x.dx`


Evaluate the following : `int cos sqrt(x).dx`


Integrate the following functions w.r.t. x : `sqrt(5x^2 + 3)`


Integrate the following functions w.r.t. x : `xsqrt(5 - 4x - x^2)`


Integrate the following functions w.r.t. x: `sqrt(x^2 + 2x + 5)`.


Integrate the following functions w.r.t. x : `sqrt(2x^2 + 3x + 4)`


Integrate the following functions w.r.t. x : `((1 + sin x)/(1 + cos x)).e^x`


Integrate the following functions w.r.t. x : `e^x .(1/x - 1/x^2)`


Integrate the following functions w.r.t. x : `e^x/x [x (logx)^2 + 2 (logx)]`


Choose the correct options from the given alternatives :

`int tan(sin^-1 x)*dx` =


Choose the correct options from the given alternatives :

`int [sin (log x) + cos (log x)]*dx` =


Integrate the following with respect to the respective variable : cos 3x cos 2x cos x


Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`


Integrate the following w.r.t.x : `(1)/(x^3 sqrt(x^2 - 1)`


Evaluate the following.

`int x^2 e^4x`dx


Evaluate the following.

`int (log "x")/(1 + log "x")^2` dx


Choose the correct alternative from the following.

`int (("e"^"2x" + "e"^"-2x")/"e"^"x") "dx"` = 


Choose the correct alternative from the following.

`int (1 - "x")^(-2) "dx"` = 


Evaluate: `int "dx"/(3 - 2"x" - "x"^2)`


Evaluate: `int "dx"/("9x"^2 - 25)`


Evaluate: `int "dx"/(5 - 16"x"^2)`


`int ["cosec"(logx)][1 - cot(logx)]  "d"x`


Choose the correct alternative:

`int ("d"x)/((x - 8)(x + 7))` =


`int (x^2 + x - 6)/((x - 2)(x - 1))  "d"x` = x + ______ + c


The value of `int "e"^(5x) (1/x - 1/(5x^2))  "d"x` is ______.


`int "e"^x int [(2 - sin 2x)/(1 - cos 2x)]`dx = ______.


Find `int_0^1 x(tan^-1x)  "d"x`


The value of `int_0^(pi/2) log ((4 + 3 sin x)/(4 + 3 cos x))  dx` is


`int 1/sqrt(x^2 - a^2)dx` = ______.


Solve: `int sqrt(4x^2 + 5)dx`


`int e^x [(2 + sin 2x)/(1 + cos 2x)]dx` = ______.


`int_0^1 x tan^-1 x  dx` = ______.


`int1/sqrt(x^2 - a^2) dx` = ______


Solution of the equation `xdy/dx=y log y` is ______


The integrating factor of `ylogy.dx/dy+x-logy=0` is ______.


`int(f'(x))/sqrt(f(x)) dx = 2sqrt(f(x))+c`


If u and v are two differentiable functions of x, then prove that `intu*v*dx = u*intv  dx - int(d/dx u)(intv  dx)dx`. Hence evaluate: `intx cos x  dx`


Evaluate the following:

`intx^3e^(x^2)dx` 


The value of `inta^x.e^x dx` equals


Evaluate:

`inte^x "cosec"  x(1 - cot x)dx`


Evaluate `int(1 + x + x^2/(2!))dx`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×