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Question
Integrate the function in x log x.
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Solution
Let `I = int x log x dx`
`= log x int x dx - int [d/dx (log x) int x dx] dx`
`= log x (x^2/2) - int (1/x * x^2/2) dx`
`= x^2/2 log x - 1/2 int x dx + C`
`= x^2/2 log x -1/2 xx x^2/2 + C`
`= x^2/2 log x - 1/4 x^2 + C`
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