English

Integrate the function in (x-3)ex(x-1)3. - Mathematics

Advertisements
Advertisements

Question

Integrate the function in `((x- 3)e^x)/(x - 1)^3`.

Sum
Advertisements

Solution

Let `I = ((x - 3) e^x)/(x - 1)^3  dx`

`= int (e^x (x - 1 - 2))/(x - 1)^3  dx`

`= int e^x [1/((x - 1)^2) - 2/((x - 1)^3)]  dx`

On substituting `e^x . 1/((x - 1)^2) = t`

`[e^x - 2 (x - 1)^-3 + 1/((x - 1)^2). e^x]  dx = dt`

or `e^x [1/((x - 1)^2) - 2/(x - 1)^3] dx = dt`

Hence, `I = int 1. dt = t + C`

`= e^x/((x - 1)^2) + C`

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Integrals - Exercise 7.6 [Page 328]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.6 | Q 20 | Page 328

RELATED QUESTIONS

Integrate the function in `x^2e^x`.


Integrate the function in x tan-1 x.


Integrate the function in `sin^(-1) ((2x)/(1+x^2))`.


`intx^2 e^(x^3) dx` equals: 


Evaluate the following : `int x^2tan^-1x.dx`


Evaluate the following : `int sin θ.log (cos θ).dθ`


Integrate the following functions w.r.t. x : `sqrt(4^x(4^x + 4))`


Choose the correct options from the given alternatives :

`int tan(sin^-1 x)*dx` =


Choose the correct options from the given alternatives :

`int (1)/(cosx - cos^2x)*dx` =


Choose the correct options from the given alternatives :

`int cos -(3)/(7)x*sin -(11)/(7)x*dx` =


Choose the correct options from the given alternatives :

`int [sin (log x) + cos (log x)]*dx` =


Integrate the following with respect to the respective variable : `(sin^6θ + cos^6θ)/(sin^2θ*cos^2θ)`


Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`


Integrate the following w.r.t.x : log (x2 + 1)


Integrate the following w.r.t.x : sec4x cosec2x


Evaluate the following.

`int "e"^"x" "x - 1"/("x + 1")^3` dx


Evaluate the following.

`int [1/(log "x") - 1/(log "x")^2]` dx


Evaluate: `int ("ae"^("x") + "be"^(-"x"))/("ae"^("x") - "be"^(−"x"))` dx


`int (cos2x)/(sin^2x cos^2x)  "d"x`


Evaluate `int 1/(x log x)  "d"x`


`int cot "x".log [log (sin "x")] "dx"` = ____________.


The value of `int "e"^(5x) (1/x - 1/(5x^2))  "d"x` is ______.


Evaluate the following:

`int (sin^-1 x)/((1 - x)^(3/2)) "d"x`


Evaluate the following:

`int ((cos 5x + cos 4x))/(1 - 2 cos 3x) "d"x`


`int tan^-1 sqrt(x)  "d"x` is equal to ______.


The value of `int_0^(pi/2) log ((4 + 3 sin x)/(4 + 3 cos x))  dx` is


State whether the following statement is true or false.

If `int (4e^x - 25)/(2e^x - 5)` dx = Ax – 3 log |2ex – 5| + c, where c is the constant of integration, then A = 5.


The integral `int x cos^-1 ((1 - x^2)/(1 + x^2))dx (x > 0)` is equal to ______.


Solution of the equation `xdy/dx=y log y` is ______


Evaluate the following.

`int x^3 e^(x^2) dx`


Evaluate: 

`int(1+logx)/(x(3+logx)(2+3logx))  dx`


Evaluate `int(3x-2)/((x+1)^2(x+3))  dx`


Solve the differential equation (x2 + y2) dx - 2xy dy = 0 by completing the following activity.

Solution: (x2 + y2) dx - 2xy dy = 0

∴ `dy/dx=(x^2+y^2)/(2xy)`                      ...(1)

Puty = vx

∴ `dy/dx=square`

∴ equation (1) becomes

`x(dv)/dx = square`

∴ `square  dv = dx/x`

On integrating, we get

`int(2v)/(1-v^2) dv =intdx/x`

∴ `-log|1-v^2|=log|x|+c_1`

∴ `log|x| + log|1-v^2|=logc       ...["where" - c_1 = log c]`

∴ x(1 - v2) = c

By putting the value of v, the general solution of the D.E. is `square`= cx


Evaluate:

`int((1 + sinx)/(1 + cosx))e^x dx`


Evaluate `int tan^-1x  dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)


Evaluate the following.

`int x^3 e^(x^2) dx` 


Evaluate the following.

`intx^2e^(4x)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×