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Integrate the function in e2x sin x.

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Question

Integrate the function in e2x sin x.

Sum
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Solution

Let `I = inte^(2x) sinx dx`

`= e^(2x) int sin x dx - int [d/dx (e^(2x))* int sin x dx] dx`

`= e^(2x) (- cos x) - int 2e^(2x) (- cos x) dx + C_1`

`= -e^(2x) cos x + 2 int e^(2x) cos x dx + C_1`

`= -e^(2x) cos x + 2`       `...[e^(2x) int cos x dx - int (d/dx (e^(2x))* int cos xdx)  dx] + C_1`

`= -e^(2x) cos x + 2e^(2x) sin x - 4 int e^(2x) sin x dx + C_1 + C_2`

`= e^(2x) (2 sin x - cos x) - 4I + C_1 + C_2`

∵ `5I = e^(2x) (2 sinx - cos x) + C_1 + C_2`

⇒ `I = (e^(2x))/5 (2 sin x - cos x) + C`

where C = C1 + C2

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Chapter 7: Integrals - Exercise 7.6 [Page 328]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.6 | Q 21 | Page 328

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