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Evaluate the following : ∫x2.logx.dx

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Question

Evaluate the following : `int x^2.log x.dx`

Sum
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Solution

Let I = `int x^2.logx.dx`

= `int log x.x^2.dx`

= `(logx) int x^2.dx - int[{d/dx (logx) int x^2.dx}].dx`

= `(logx).x^3/(3) - int (1)/x.x^3/(3).dx`

= `x^3/(3) logx - (1)/(3) int x^2.dx`

= `x^3/(3) logx - (1)/(3)(x^3/3) + c`

= `x^3/(9)(3.logx - 1) + c`.

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Chapter 3: Indefinite Integration - Exercise 3.3 [Page 137]

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