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Question
Evaluate the following : `int (t.sin^-1 t)/sqrt(1 - t^2).dt`
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Solution
Let I = `int (t.sin^-1 t)/sqrt(1 - t^2).dt`
= `int t.sin^-1 t. 1/sqrt(1 - t^2).dt`
Put sin–1 t = θ
∴ `1/sqrt(1 - t^2).dt` = dθ
and
t = sin θ
∴ I = `int (sinθ).θdθ`
= `int θ sin θ dθ`
= `θ int sin θ dθ - int [d/(dθ) (θ) int sin θ dθ]dθ`
= `θ (- cos θ) - int 1. (- cosθ)dθ`
= `- θ cosθ + int cosθ dθ`
= – θ cos θ + sin θ + c
= `- θ.sqrt(1 - sin^2θ) + sin θ + c`
= `- sin^-1 t.sqrt(1 - t^2) + t + c`
= `- sqrt(1 - t^2).sin^-1 t + t + c`.
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