English

Evaluate the following : ∫cosx.dx

Advertisements
Advertisements

Question

Evaluate the following : `int cos sqrt(x).dx`

Sum
Advertisements

Solution

Let I = `int cos sqrt(x).dx`
Put `sqrt(x) = t`
∴ x = t2
∴ dx = 2t .dt
∴ I = `int(cost)2t.dt`

= `int 2t cos t.dt`

= `2t int cos.dt - int [d/dt (2t) int cos t.dt ].dt`

= `2tsint - int 2 sint.dt`

= 2t sin t + 2 cos t + c

= `2[sqrt(x)sinsqrt(x) + cos sqrt(x)] + c`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Exercise 3.3 [Page 137]

APPEARS IN

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Integrate : sec3 x w. r. t. x.


If u and v are two functions of x then prove that

`intuvdx=uintvdx-int[du/dxintvdx]dx`

Hence evaluate, `int xe^xdx`


Integrate the function in `x^2e^x`.


Integrate the function in x log 2x.


Integrate the function in xlog x.


Integrate the function in x (log x)2.


Integrate the function in `(xe^x)/(1+x)^2`.


Integrate the function in `e^x (1 + sin x)/(1+cos x)`.


Integrate the function in `e^x (1/x - 1/x^2)`.


Evaluate the following : `int x^2tan^-1x.dx`


Evaluate the following : `int e^(2x).cos 3x.dx`


Evaluate the following : `int x.cos^3x.dx`


Integrate the following functions w.r.t. x : `e^(2x).sin3x`


Integrate the following functions w.r.t. x:

sin (log x)


Integrate the following functions w.r.t. x : `x^2 .sqrt(a^2 - x^6)`


Integrate the following functions w.r.t. x : `sqrt((x - 3)(7 - x)`


Integrate the following functions w.r.t. x : `(x + 1) sqrt(2x^2 + 3)`


Integrate the following functions w.r.t. x : `e^x/x [x (logx)^2 + 2 (logx)]`


Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`


Integrate the following functions w.r.t. x : `e^(sin^-1x)*[(x + sqrt(1 - x^2))/sqrt(1 - x^2)]`


Choose the correct options from the given alternatives :

`int (1)/(x + x^5)*dx` = f(x) + c, then `int x^4/(x + x^5)*dx` =


Choose the correct options from the given alternatives :

`int tan(sin^-1 x)*dx` =


Choose the correct options from the given alternatives :

`int [sin (log x) + cos (log x)]*dx` =


Integrate the following w.r.t. x: `(1 + log x)^2/x`


Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`


Integrate the following w.r.t.x : `(1)/(x^3 sqrt(x^2 - 1)`


Solve the following differential equation.

(x2 − yx2 ) dy + (y2 + xy2) dx = 0


Evaluate the following.

`int x^2 e^4x`dx


Evaluate the following.

`int (log "x")/(1 + log "x")^2` dx


Evaluate: `int "dx"/(25"x" - "x"(log "x")^2)`


`int (sin(x - "a"))/(cos (x + "b"))  "d"x`


`int (cos2x)/(sin^2x cos^2x)  "d"x`


Evaluate `int 1/(x(x - 1))  "d"x`


Evaluate `int 1/(x log x)  "d"x`


Evaluate `int (2x + 1)/((x + 1)(x - 2))  "d"x`


The value of `int "e"^(5x) (1/x - 1/(5x^2))  "d"x` is ______.


`int 1/sqrt(x^2 - a^2)dx` = ______.


Solve: `int sqrt(4x^2 + 5)dx`


`int(logx)^2dx` equals ______.


`int_0^1 x tan^-1 x  dx` = ______.


Find: `int e^(x^2) (x^5 + 2x^3)dx`.


`int logx  dx = x(1+logx)+c`


`int(xe^x)/((1+x)^2)  dx` = ______


Evaluate:

`int e^(logcosx)dx`


Prove that `int sqrt(x^2 - a^2)dx = x/2 sqrt(x^2 - a^2) - a^2/2 log(x + sqrt(x^2 - a^2)) + c`


If u and v are two differentiable functions of x, then prove that `intu*v*dx = u*intv  dx - int(d/dx u)(intv  dx)dx`. Hence evaluate: `intx cos x  dx`


Evaluate the following:

`intx^3e^(x^2)dx` 


Evaluate:

`int x^2 cos x  dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×