Advertisements
Advertisements
Question
Choose the correct alternative:
`int ("d"x)/((x - 8)(x + 7))` =
Options
`1/15 log((x + 2)/(x - 1)) + "c"`
`1/15 log((x + 8)/(x + 7)) + "c"`
`1/15 log((x - 8)/(x + 7)) + "c"`
(x – 8)(x – 7) + c
Advertisements
Solution
`1/15 log((x - 8)/(x + 7)) + "c"`
APPEARS IN
RELATED QUESTIONS
Integrate : sec3 x w. r. t. x.
Integrate the function in x log x.
Integrate the function in `e^x (1/x - 1/x^2)`.
`int e^x sec x (1 + tan x) dx` equals:
Find :
`∫(log x)^2 dx`
Evaluate the following : `int x^2tan^-1x.dx`
Evaluate the following : `int(sin(logx)^2)/x.log.x.dx`
Integrate the following functions w.r.t. x : `e^(2x).sin3x`
Integrate the following functions w.r.t. x : `sqrt(5x^2 + 3)`
Integrate the following functions w.r.t. x : `x^2 .sqrt(a^2 - x^6)`
Integrate the following functions w.r.t. x : `log(1 + x)^((1 + x)`
Choose the correct options from the given alternatives :
`int (1)/(x + x^5)*dx` = f(x) + c, then `int x^4/(x + x^5)*dx` =
Integrate the following with respect to the respective variable : `(sin^6θ + cos^6θ)/(sin^2θ*cos^2θ)`
Integrate the following w.r.t.x : cot–1 (1 – x + x2)
Evaluate the following.
∫ x log x dx
Choose the correct alternative from the following.
`int (("e"^"2x" + "e"^"-2x")/"e"^"x") "dx"` =
Evaluate: `int "dx"/(3 - 2"x" - "x"^2)`
Evaluate: `int "dx"/(5 - 16"x"^2)`
Evaluate `int 1/(x(x - 1)) "d"x`
Evaluate `int 1/(x log x) "d"x`
∫ log x · (log x + 2) dx = ?
Evaluate: `int_0^(pi/4) (dx)/(1 + tanx)`
Find: `int e^(x^2) (x^5 + 2x^3)dx`.
`int(3x^2)/sqrt(1+x^3) dx = sqrt(1+x^3)+c`
Evaluate `int(3x-2)/((x+1)^2(x+3)) dx`
Evaluate the following.
`int (x^3)/(sqrt(1 + x^4))dx`
`int (sin^-1 sqrt(x) + cos^-1 sqrt(x))dx` = ______.
Evaluate `int tan^-1x dx`
Repeated parts may be needed for which pair of integrals?
