Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
`int ("d"x)/((x - 8)(x + 7))` =
पर्याय
`1/15 log((x + 2)/(x - 1)) + "c"`
`1/15 log((x + 8)/(x + 7)) + "c"`
`1/15 log((x - 8)/(x + 7)) + "c"`
(x – 8)(x – 7) + c
Advertisements
उत्तर
`1/15 log((x - 8)/(x + 7)) + "c"`
APPEARS IN
संबंधित प्रश्न
Integrate the function in x sec2 x.
Integrate the function in x (log x)2.
Integrate the function in (x2 + 1) log x.
Integrate the function in e2x sin x.
Evaluate the following : `int x^3.tan^-1x.dx`
Evaluate the following: `int x.sin^-1 x.dx`
Choose the correct options from the given alternatives :
`int (1)/(x + x^5)*dx` = f(x) + c, then `int x^4/(x + x^5)*dx` =
Integrate the following with respect to the respective variable : `t^3/(t + 1)^2`
Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`
Integrate the following w.r.t.x : log (x2 + 1)
Evaluate the following.
`int e^x (1/x - 1/x^2)`dx
Evaluate: `int "dx"/("x"[(log "x")^2 + 4 log "x" - 1])`
Evaluate: `int "e"^"x"/(4"e"^"2x" -1)` dx
`int (sin(x - "a"))/(cos (x + "b")) "d"x`
`int sin4x cos3x "d"x`
`int"e"^(4x - 3) "d"x` = ______ + c
Evaluate `int (2x + 1)/((x + 1)(x - 2)) "d"x`
∫ log x · (log x + 2) dx = ?
`int log x * [log ("e"x)]^-2` dx = ?
Evaluate the following:
`int ((cos 5x + cos 4x))/(1 - 2 cos 3x) "d"x`
Evaluate the following:
`int_0^1 x log(1 + 2x) "d"x`
Find the general solution of the differential equation: `e^((dy)/(dx)) = x^2`.
If `int(2e^(5x) + e^(4x) - 4e^(3x) + 4e^(2x) + 2e^x)/((e^(2x) + 4)(e^(2x) - 1)^2)dx = tan^-1(e^x/a) - 1/(b(e^(2x) - 1)) + C`, where C is constant of integration, then value of a + b is equal to ______.
`int_0^1 x tan^-1 x dx` = ______.
`int1/sqrt(x^2 - a^2) dx` = ______
Solution of the equation `xdy/dx=y log y` is ______
Evaluate the following.
`intx^3e^(x^2) dx`
Evaluate the following.
`int x sqrt(1 + x^2) dx`
