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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

D∫dxx-x2 = ______ - Mathematics and Statistics

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प्रश्न

`int ("d"x)/(x - x^2)` = ______

पर्याय

  • log x – log(1 – x) + c

  • log(1 – x2) + c

  • – log x + log(1 – x) + c

  • log(x – x2) + c

MCQ
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उत्तर

`int ("d"x)/(x - x^2)` = log x – log(1 – x) + c 

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पाठ 1.5: Integration - Q.1

संबंधित प्रश्‍न

Prove that: `int sqrt(a^2 - x^2) * dx = x/2 * sqrt(a^2 - x^2) + a^2/2 * sin^-1(x/a) + c`


Integrate the function in x tan-1 x.


Integrate the function in `((x- 3)e^x)/(x - 1)^3`.


Evaluate the following : `int e^(2x).cos 3x.dx`


Integrate the following functions w.r.t. x : `sqrt((x - 3)(7 - x)`


Integrate the following functions w.r.t. x : `(x + 1) sqrt(2x^2 + 3)`


Integrate the following functions w.r.t. x : `sec^2x.sqrt(tan^2x + tan x - 7)`


Integrate the following functions w.r.t. x : [2 + cot x – cosec2x]e 


Choose the correct options from the given alternatives :

`int (1)/(x + x^5)*dx` = f(x) + c, then `int x^4/(x + x^5)*dx` =


Integrate the following w.r.t.x : `log (1 + cosx) - xtan(x/2)`


Evaluate the following.

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`int "e"^"x" [(log "x")^2 + (2 log "x")/"x"]` dx


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Evaluate the following:

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Evaluate the following:

`int_0^pi x log sin x "d"x`


`int 1/sqrt(x^2 - 9) dx` = ______.


Solve: `int sqrt(4x^2 + 5)dx`


If `int(x + (cos^-1 3x)^2)/sqrt(1 - 9x^2)dx = 1/α(sqrt(1 - 9x^2) + (cos^-1 3x)^β) + C`, where C is constant of integration , then (α + 3β) is equal to ______.


Solve the differential equation (x2 + y2) dx - 2xy dy = 0 by completing the following activity.

Solution: (x2 + y2) dx - 2xy dy = 0

∴ `dy/dx=(x^2+y^2)/(2xy)`                      ...(1)

Puty = vx

∴ `dy/dx=square`

∴ equation (1) becomes

`x(dv)/dx = square`

∴ `square  dv = dx/x`

On integrating, we get

`int(2v)/(1-v^2) dv =intdx/x`

∴ `-log|1-v^2|=log|x|+c_1`

∴ `log|x| + log|1-v^2|=logc       ...["where" - c_1 = log c]`

∴ x(1 - v2) = c

By putting the value of v, the general solution of the D.E. is `square`= cx


Solve the following

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`int_0^2 dx/(4 + x - x^2) `

= `int_0^2 dx/(-x^2 + square + square)`

= `int_0^2 dx/(-x^2 + x + 1/4 - square + 4)`

= `int_0^2 dx/ ((x- 1/2)^2 - (square)^2)`

= `1/sqrt17 log((20 + 4sqrt17)/(20 - 4sqrt17))`


Evaluate:

`int x^2 cos x  dx`


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