मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Choose the correct options from the given alternatives : ∫[sin(logx)+cos(logx)]⋅dx =

Advertisements
Advertisements

प्रश्न

Choose the correct options from the given alternatives :

`int [sin (log x) + cos (log x)]*dx` =

पर्याय

  • x cos (log x) + c

  • sin (log x) + c

  • cos (log x) + c

  • x sin (log x) + c

MCQ
Advertisements

उत्तर

x sin (log x) + c

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Miscellaneous Exercise 3 [पृष्ठ १५०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.18 | पृष्ठ १५०

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Prove that: `int sqrt(a^2 - x^2) * dx = x/2 * sqrt(a^2 - x^2) + a^2/2 * sin^-1(x/a) + c`


Integrate : sec3 x w. r. t. x.


If `int_(-pi/2)^(pi/2)sin^4x/(sin^4x+cos^4x)dx`, then the value of I is:

(A) 0

(B) π

(C) π/2

(D) π/4


Integrate the function in x sin x.


Integrate the function in x sin 3x.


Integrate the function in x log 2x.


Integrate the function in x tan-1 x.


Integrate the function in `e^x (1 + sin x)/(1+cos x)`.


Evaluate the following:

`int x^2 sin 3x  dx`


Evaluate the following : `int x^2*cos^-1 x*dx`


Evaluate the following : `int (t.sin^-1 t)/sqrt(1 - t^2).dt`


Evaluate the following : `int(sin(logx)^2)/x.log.x.dx`


Integrate the following functions w.r.t. x : `sqrt(4^x(4^x + 4))`


Integrate the following functions w.r.t. x : `[x/(x + 1)^2].e^x`


Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`


Integrate the following functions w.r.t. x : `e^(sin^-1x)*[(x + sqrt(1 - x^2))/sqrt(1 - x^2)]`


If f(x) = `sin^-1x/sqrt(1 - x^2), "g"(x) = e^(sin^-1x)`, then `int f(x)*"g"(x)*dx` = ______.


Integrate the following w.r.t.x : cot–1 (1 – x + x2)


Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`


Integrate the following w.r.t.x : log (log x)+(log x)–2 


Evaluate the following.

`int "e"^"x" "x - 1"/("x + 1")^3` dx


Evaluate: `int "dx"/sqrt(4"x"^2 - 5)`


`int (sin(x - "a"))/(cos (x + "b"))  "d"x`


`int sin4x cos3x  "d"x`


Choose the correct alternative:

`intx^(2)3^(x^3) "d"x` =


State whether the following statement is true or false.

If `int (4e^x - 25)/(2e^x - 5)` dx = Ax – 3 log |2ex – 5| + c, where c is the constant of integration, then A = 5.


Evaluate: `int_0^(pi/4) (dx)/(1 + tanx)`


Find: `int e^x.sin2xdx`


`int 1/sqrt(x^2 - a^2)dx` = ______.


If `int(2e^(5x) + e^(4x) - 4e^(3x) + 4e^(2x) + 2e^x)/((e^(2x) + 4)(e^(2x) - 1)^2)dx = tan^-1(e^x/a) - 1/(b(e^(2x) - 1)) + C`, where C is constant of integration, then value of a + b is equal to ______.


`int e^x [(2 + sin 2x)/(1 + cos 2x)]dx` = ______.


Evaluate :

`int(4x - 6)/(x^2 - 3x + 5)^(3/2)  dx`


`intsqrt(1+x)  dx` = ______


Solution of the equation `xdy/dx=y log y` is ______


Solve the differential equation (x2 + y2) dx - 2xy dy = 0 by completing the following activity.

Solution: (x2 + y2) dx - 2xy dy = 0

∴ `dy/dx=(x^2+y^2)/(2xy)`                      ...(1)

Puty = vx

∴ `dy/dx=square`

∴ equation (1) becomes

`x(dv)/dx = square`

∴ `square  dv = dx/x`

On integrating, we get

`int(2v)/(1-v^2) dv =intdx/x`

∴ `-log|1-v^2|=log|x|+c_1`

∴ `log|x| + log|1-v^2|=logc       ...["where" - c_1 = log c]`

∴ x(1 - v2) = c

By putting the value of v, the general solution of the D.E. is `square`= cx


`int logx  dx = x(1+logx)+c`


Evaluate the following.

`int (x^3)/(sqrt(1 + x^4))dx`


Evaluate:

`int1/(x^2 + 25)dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)  dx`


Evaluate:

`int x^2 cos x  dx`


Evaluate the following.

`intx^3/(sqrt(1 + x^4))dx`


Which expression is the integration-by-parts form for a product \(f(x)g(x)\)?


Evaluate \[\int x\cos x\,dx.\]


Let \[I=\int e^x\sin x\,dx.\] After applying integration by parts once, which equation is obtained?


Which differentiation identity verifies the special integral \[\int e^x\left[f(x)+f'(x)\right]dx=e^xf(x)+C?\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×