मराठी

Find: ∫ex2(x5+2x3)dx.

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प्रश्न

Find: `int e^(x^2) (x^5 + 2x^3)dx`.

बेरीज
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उत्तर

I = `int e^(x^2) (x^5 + 2x^3)dx`

I = `int x^5 e^(x^2) dx + 2int x^3 e^(x^2) dx`

Applying integration by part in `int x^3e^(x^2) dx`

I = `int x^5 e^(x^2) dx + (2x^4)/4 e^(x^2) - 2int e^(x^2) 2x . x^4/4 dx`

= `int x^5e^(x^2) dx + (2x^4e^(x^2))/4 - 2int (x^5e^(x^2))/2dx`

= `(x^4e^(x^2))/2 + C`.

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2022-2023 (March) Delhi Set 2

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