मराठी

Find: ∫ex2(x5+2x3)dx.

Advertisements
Advertisements

प्रश्न

Find: `int e^(x^2) (x^5 + 2x^3)dx`.

बेरीज
Advertisements

उत्तर

I = `int e^(x^2) (x^5 + 2x^3)dx`

I = `int x^5 e^(x^2) dx + 2int x^3 e^(x^2) dx`

Applying integration by part in `int x^3e^(x^2) dx`

I = `int x^5 e^(x^2) dx + (2x^4)/4 e^(x^2) - 2int e^(x^2) 2x . x^4/4 dx`

= `int x^5e^(x^2) dx + (2x^4e^(x^2))/4 - 2int (x^5e^(x^2))/2dx`

= `(x^4e^(x^2))/2 + C`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2022-2023 (March) Delhi Set 2

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

If `int_(-pi/2)^(pi/2)sin^4x/(sin^4x+cos^4x)dx`, then the value of I is:

(A) 0

(B) π

(C) π/2

(D) π/4


If u and v are two functions of x then prove that

`intuvdx=uintvdx-int[du/dxintvdx]dx`

Hence evaluate, `int xe^xdx`


Integrate the function in `x^2e^x`.


Integrate the function in x sin−1 x.


Integrate the function in x cos-1 x.


Integrate the function in `((x- 3)e^x)/(x - 1)^3`.


Integrate the function in e2x sin x.


Evaluate the following: `int x.sin^-1 x.dx`


Evaluate the following : `int log(logx)/x.dx`


Evaluate the following : `int cos sqrt(x).dx`


Evaluate the following : `int sin θ.log (cos θ).dθ`


Evaluate the following : `int x.cos^3x.dx`


Integrate the following functions w.r.t. x : `sqrt(4^x(4^x + 4))`


Integrate the following functions w.r.t. x : [2 + cot x – cosec2x]e 


Integrate the following functions w.r.t. x : `e^x .(1/x - 1/x^2)`


Integrate the following functions w.r.t. x : `e^x/x [x (logx)^2 + 2 (logx)]`


Integrate the following functions w.r.t. x : `e^(sin^-1x)*[(x + sqrt(1 - x^2))/sqrt(1 - x^2)]`


Integrate the following with respect to the respective variable : cos 3x cos 2x cos x


Evaluate: `int "dx"/sqrt(4"x"^2 - 5)`


`int "dx"/(sin(x - "a")sin(x - "b"))` is equal to ______.


The value of `int_0^(pi/2) log ((4 + 3 sin x)/(4 + 3 cos x))  dx` is


`int 1/sqrt(x^2 - a^2)dx` = ______.


Solve: `int sqrt(4x^2 + 5)dx`


The integral `int x cos^-1 ((1 - x^2)/(1 + x^2))dx (x > 0)` is equal to ______.


Evaluate :

`int(4x - 6)/(x^2 - 3x + 5)^(3/2)  dx`


Evaluate `int(3x-2)/((x+1)^2(x+3))  dx`


Solve the differential equation (x2 + y2) dx - 2xy dy = 0 by completing the following activity.

Solution: (x2 + y2) dx - 2xy dy = 0

∴ `dy/dx=(x^2+y^2)/(2xy)`                      ...(1)

Puty = vx

∴ `dy/dx=square`

∴ equation (1) becomes

`x(dv)/dx = square`

∴ `square  dv = dx/x`

On integrating, we get

`int(2v)/(1-v^2) dv =intdx/x`

∴ `-log|1-v^2|=log|x|+c_1`

∴ `log|x| + log|1-v^2|=logc       ...["where" - c_1 = log c]`

∴ x(1 - v2) = c

By putting the value of v, the general solution of the D.E. is `square`= cx


Solve the following

`int_0^1 e^(x^2) x^3 dx`


Evaluate:

`int (logx)^2 dx`


Evaluate the following.

`intx^2e^(4x)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×