मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Integrate the following functions w.r.t. x : cosec (log x)[1 – cot (log x)] - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Integrate the following functions w.r.t. x : cosec (log x)[1 – cot (log x)] 

बेरीज
Advertisements

उत्तर

Let I = `int "cosec" (log x)[1 - cot (log x)].dx`
Put log x = t
∴ et
∴ dx = et .dt

∴ I = `int "cosec" t (1 - cot t).e^t dt`

= `int e^t ["cosec"  t - "cosec"  t cot t].dt`

= `int e^t ["cosec"  t + d/dt ("cosec"  t)].dt`

= `e^t "cosec" t + c     ...[∵ int e^t [f(t) + f'(t)].dt = e^t f(t) + c]`

= x . cosec (log x) + c.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Exercise 3.3 [पृष्ठ १३८]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.3 | Q 3.9 | पृष्ठ १३८

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Integrate the function in x log x.


`intx^2 e^(x^3) dx` equals: 


`int e^x sec x (1 +   tan x) dx` equals:


Evaluate the following:

`int x^2 sin 3x  dx`


Evaluate the following : `int x^3.tan^-1x.dx`


Evaluate the following:

`int sec^3x.dx`


Evaluate the following : `int x^3.logx.dx`


Evaluate the following : `int log(logx)/x.dx`


Evaluate the following : `int (t.sin^-1 t)/sqrt(1 - t^2).dt`


Evaluate the following : `int x.cos^3x.dx`


Evaluate the following : `int(sin(logx)^2)/x.log.x.dx`


Evaluate the following : `int cos(root(3)(x)).dx`


Integrate the following functions w.r.t. x : `x^2 .sqrt(a^2 - x^6)`


If f(x) = `sin^-1x/sqrt(1 - x^2), "g"(x) = e^(sin^-1x)`, then `int f(x)*"g"(x)*dx` = ______.


Integrate the following with respect to the respective variable : `(sin^6θ + cos^6θ)/(sin^2θ*cos^2θ)`


Integrate the following with respect to the respective variable : cos 3x cos 2x cos x


Integrate the following w.r.t. x: `(1 + log x)^2/x`


Evaluate the following.

∫ x log x dx


Evaluate the following.

`int x^2 e^4x`dx


Evaluate the following.

`int "e"^"x" "x"/("x + 1")^2` dx


Choose the correct alternative from the following.

`int (1 - "x")^(-2) "dx"` = 


Evaluate: `int "e"^"x"/(4"e"^"2x" -1)` dx


`int (sinx)/(1 + sin x)  "d"x`


`int 1/(4x + 5x^(-11))  "d"x`


Evaluate `int 1/(x log x)  "d"x`


`int [(log x - 1)/(1 + (log x)^2)]^2`dx = ?


`int cot "x".log [log (sin "x")] "dx"` = ____________.


`int "e"^x int [(2 - sin 2x)/(1 - cos 2x)]`dx = ______.


Evaluate the following:

`int_0^1 x log(1 + 2x)  "d"x`


Solve: `int sqrt(4x^2 + 5)dx`


`int(logx)^2dx` equals ______.


If `int(x + (cos^-1 3x)^2)/sqrt(1 - 9x^2)dx = 1/α(sqrt(1 - 9x^2) + (cos^-1 3x)^β) + C`, where C is constant of integration , then (α + 3β) is equal to ______.


Find `int e^x ((1 - sinx)/(1 - cosx))dx`.


`int1/sqrt(x^2 - a^2) dx` = ______


The integrating factor of `ylogy.dx/dy+x-logy=0` is ______.


Evaluate:

`intcos^-1(sqrt(x))dx`


Evaluate `int tan^-1x  dx`


Evaluate:

`int (sin(x - a))/(sin(x + a))dx`


If u and v are two differentiable functions of x, then prove that `intu*v*dx = u*intv  dx - int(d/dx u)(intv  dx)dx`. Hence evaluate: `intx cos x  dx`


Complete the following activity:

`int_0^2 dx/(4 + x - x^2) `

= `int_0^2 dx/(-x^2 + square + square)`

= `int_0^2 dx/(-x^2 + x + 1/4 - square + 4)`

= `int_0^2 dx/ ((x- 1/2)^2 - (square)^2)`

= `1/sqrt17 log((20 + 4sqrt17)/(20 - 4sqrt17))`


Evaluate the following.

`intx^3/sqrt(1+x^4)dx`


Evaluate the following.

`intx^3 e^(x^2) dx`


If ∫(cot x – cosec2 x)ex dx = ex f(x) + c then f(x) will be ______.


Evaluate:

`int x^2 cos x  dx`


Evaluate the following.

`intx^2e^(4x)dx`


The value of `inta^x.e^x dx` equals


Evaluate:

`inte^x "cosec"  x(1 - cot x)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×