मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Evaluate the following : ∫sec3x.dx - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Evaluate the following:

`int sec^3x.dx`

बेरीज
Advertisements

उत्तर

Let I = `int sec^3x.dx`

= `int sec x sec^2x.dx`

= `sec x int sec^2x.dx - int[d/dx(secx) int sec^2x.dx].dx`

= `secx tanx- int (secx tanx)(tanx).dx`

= `secx tanx - int secx tan^2x.dx`

= `secx tanx - int secx (sec^2x - 1).dx`

= `secx tanx - int sec^3x.dx + int secx.dx`

∴ I = sec x tan x – I + log |sec x + tanx|

∴ 2I = sec x tan x + log |sec x  + tan x|

∴ I = `(1)/(2)[secx tanx + log |secx + tan|] + c`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Exercise 3.3 [पृष्ठ १३७]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.3 | Q 1.07 | पृष्ठ १३७

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

If u and v are two functions of x then prove that

`intuvdx=uintvdx-int[du/dxintvdx]dx`

Hence evaluate, `int xe^xdx`


Integrate the function in xlog x.


Integrate the function in `(x cos^(-1) x)/sqrt(1-x^2)`.


Integrate the function in ex (sinx + cosx).


Integrate the function in e2x sin x.


`int e^x sec x (1 +   tan x) dx` equals:


Evaluate the following:

`int x tan^-1 x . dx`


Evaluate the following : `int x^2tan^-1x.dx`


Evaluate the following : `int sin θ.log (cos θ).dθ`


Integrate the following functions w.r.t. x : `sqrt(2x^2 + 3x + 4)`


Integrate the following functions w.r.t. x : `((1 + sin x)/(1 + cos x)).e^x`


Integrate the following functions w.r.t. x : `e^x .(1/x - 1/x^2)`


Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`


Integrate the following functions w.r.t. x : `log(1 + x)^((1 + x)`


Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =


If f(x) = `sin^-1x/sqrt(1 - x^2), "g"(x) = e^(sin^-1x)`, then `int f(x)*"g"(x)*dx` = ______.


Choose the correct options from the given alternatives :

`int cos -(3)/(7)x*sin -(11)/(7)x*dx` =


Integrate the following w.r.t. x: `(1 + log x)^2/x`


Evaluate the following.

∫ x log x dx


Evaluate the following.

`int "e"^"x" "x - 1"/("x + 1")^3` dx


Evaluate: `int "dx"/("9x"^2 - 25)`


Evaluate:

∫ (log x)2 dx


`int (sinx)/(1 + sin x)  "d"x`


`int 1/sqrt(2x^2 - 5)  "d"x`


`int ["cosec"(logx)][1 - cot(logx)]  "d"x`


Evaluate `int (2x + 1)/((x + 1)(x - 2))  "d"x`


`int [(log x - 1)/(1 + (log x)^2)]^2`dx = ?


`int "e"^x [x (log x)^2 + 2 log x] "dx"` = ______.


`int "dx"/(sin(x - "a")sin(x - "b"))` is equal to ______.


If u and v ore differentiable functions of x. then prove that:

`int uv  dx = u intv  dx - int [(du)/(d) intv  dx]dx`

Hence evaluate `intlog x  dx`


Evaluate: `int_0^(pi/4) (dx)/(1 + tanx)`


Find: `int (2x)/((x^2 + 1)(x^2 + 2)) dx`


Find `int e^(cot^-1x) ((1 - x + x^2)/(1 + x^2))dx`.


Find `int (sin^-1x)/(1 - x^2)^(3//2) dx`.


Find: `int e^(x^2) (x^5 + 2x^3)dx`.


Evaluate the following.

`int x^3 e^(x^2) dx`


Solve the differential equation (x2 + y2) dx - 2xy dy = 0 by completing the following activity.

Solution: (x2 + y2) dx - 2xy dy = 0

∴ `dy/dx=(x^2+y^2)/(2xy)`                      ...(1)

Puty = vx

∴ `dy/dx=square`

∴ equation (1) becomes

`x(dv)/dx = square`

∴ `square  dv = dx/x`

On integrating, we get

`int(2v)/(1-v^2) dv =intdx/x`

∴ `-log|1-v^2|=log|x|+c_1`

∴ `log|x| + log|1-v^2|=logc       ...["where" - c_1 = log c]`

∴ x(1 - v2) = c

By putting the value of v, the general solution of the D.E. is `square`= cx


The integrating factor of `ylogy.dx/dy+x-logy=0` is ______.


`int(f'(x))/sqrt(f(x)) dx = 2sqrt(f(x))+c`


Evaluate:

`int e^(ax)*cos(bx + c)dx`


Evaluate the following.

`intx^3  e^(x^2) dx`


Evaluate the following.

`intx^3e^(x^2) dx`


Evaluate `int (1 + x + x^2/(2!))dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)


Evaluate the following.

`int x^3 e^(x^2) dx` 


Evaluate the following.

`intx^2e^(4x)dx`


Evaluate:

`inte^x "cosec"  x(1 - cot x)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×