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प्रश्न
`int 1/sqrt(x^2 - 9) dx` = ______.
पर्याय
`1/3 log |x + sqrt(x^2 - 9)| + c`
`log |x + sqrt(x^2 - 9)| + c`
`3log |x + sqrt(x^2 - 9)| + c`
`log |x - sqrt(x^2 - 9)| + c`
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उत्तर
`int 1/sqrt(x^2 - 9) dx` = `bb(log |x + sqrt(x^2 - 9)| + c)`.
Explanation:
`int 1/sqrt(x^2 - 9) dx = int 1/sqrt(x^2 - 3^2) dx`
= `log |x + sqrt(x^2 - 3^2)| + c`
= `log |x + sqrt(x^2 - 9)| + c`
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