मराठी

Integrate the function in (x2 + 1) log x.

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प्रश्न

Integrate the function in (x2 + 1) log x.

बेरीज
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उत्तर

Let `I = int (x^2 + 1) log x  dx`

`= int log x. (x^2 + 1)  dx`

Integrating piecewise by taking (log x) as the first function, we get

`I = (log x) int (x^2 + 1) dx - int [d/dx  log x int (x^2 + 1) dx] dx`

`= log x. (x^3/3 + x) - int 1/x . (x^3/3 + 1) dx`

`= (x^3/3 + x) log x - int (x^3/3 + 1)  dx`

`= (x^3/3 + x) log x - (x^3/9 + x) + C`

`= (x^3/3 + x) log x - x^3/9 - x + C`

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पाठ 7: Integrals - Exercise 7.6 [पृष्ठ ३२७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.6 | Q 15 | पृष्ठ ३२७

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