हिंदी

∫1x2-9dx = ______. - Mathematics and Statistics

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प्रश्न

`int 1/sqrt(x^2 - 9) dx` = ______.

विकल्प

  • `1/3 log |x + sqrt(x^2 - 9)| + c`

  • `log |x + sqrt(x^2 - 9)| + c`

  • `3log |x + sqrt(x^2 - 9)| + c`

  • `log |x - sqrt(x^2 - 9)| + c`

MCQ
रिक्त स्थान भरें
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उत्तर

`int 1/sqrt(x^2 - 9) dx` = `bb(log |x + sqrt(x^2 - 9)| + c)`.

Explanation:

`int 1/sqrt(x^2 - 9) dx =  int 1/sqrt(x^2 - 3^2) dx`

= `log |x + sqrt(x^2 - 3^2)| + c`

= `log |x + sqrt(x^2 - 9)| + c`

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2021-2022 (March) Set 1

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