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Choose the correct options from the given alternatives : ∫1cosx-cos2x⋅dx = - Mathematics and Statistics

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प्रश्न

Choose the correct options from the given alternatives :

`int (1)/(cosx - cos^2x)*dx` =

विकल्प

  • `log ("cosec"x - cotx) + tan(x/2) + c`

  • sin 2x – cos x + c

  • `log (secx + tanx) - cot(x/2) + c`

  • cos 2x – sin x + c

MCQ
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उत्तर

`log (secx + tanx) - cot(x/2) + c`

[ Hint : `int 1/(cosx - cos^2x)*dx`

= `int 1/(cosx(1 - cosx))*dx`

= `int ((1 - cosx) + cosx)/(cosx(1 - cosx))*dx`

= `int (1/cosx + 1/(1 - cosx))*dx`

= `int [sec x + 1/2 "cosec"^2(x/2)]*dx`

= `log|secx + tanx|1/2((-cotx/2))/(1/2) + c`

= `log|secx + tanx| - cot(x/2) + c`].

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Miscellaneous Exercise 3 [पृष्ठ १४९]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.09 | पृष्ठ १४९

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