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D∫tan-1x dx is equal to ______. - Mathematics

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प्रश्न

`int tan^-1 sqrt(x)  "d"x` is equal to ______.

विकल्प

  • `(x + 1) tan^-1 sqrt(x) - sqrt(x) + "C"`

  • `x tan^-1 sqrt(x) - sqrt(x) + "C"`

  • `sqrt(x) - x tan^-1 sqrt(x) + "C"`

  • `sqrt(x) - (x + 1) tan^-1 sqrt(x) + "C"`

MCQ
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उत्तर

`int tan^-1 sqrt(x)  "d"x` is equal to `(x + 1) tan^-1 sqrt(x) - sqrt(x) + "C"`.

Explanation:

Let I = `int 1 * tan^-1 sqrt(x)  "d"x`

= `tan^-1 sqrt(x) int 1 "d"x - int[(tan^-1  sqrt(x))"'" int 1"d"x]"d"x`

= `tan^-1 sqrt(x) * x - int 1/(1 + x) * 1/(2sqrt(x)) * x"d"x`  ....[Integrating by parrts]

= `xtan^-1 sqrt(x) - 1/2 int sqrt(x)/(1 + x) "d"x`

Put x = t2

⇒ dx = 2t dt

∴ I = `xtan^-1 sqrt(x) - int "t"^2/(1 + "t"^2) "d"x`

= `xtan^-1 sqrt(x) - int (1 - 1/(1 + "t"^2))"dt"`

= `xtan^-1 sqrt(x) - "t" + tan^-1 1 + "C"`

= `xtan^-1 sqrt(x) - sqrt(x) + tan^-1 sqrt(x) + "C"`

= `(x + 1) tan^-1 sqrt(x) - sqrt(x) + "C"`

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अध्याय 7: Integrals - Exercise [पृष्ठ १६७]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 7 Integrals
Exercise | Q 50 | पृष्ठ १६७

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