हिंदी

Choose the correct options from the given alternatives : ∫1x+x5⋅dx = f(x) + c, then ∫x4x+x5⋅dx =

Advertisements
Advertisements

प्रश्न

Choose the correct options from the given alternatives :

`int (1)/(x + x^5)*dx` = f(x) + c, then `int x^4/(x + x^5)*dx` =

विकल्प

  • log x – f(x) + c

  • f(x) + log x + c

  • f(x) – log  x + c

  • `(1)/(5) x^5f(x) + c`

MCQ
Advertisements

उत्तर

log x – f(x) + c

[Hint: `int x^4/(x + x^5)*dx = int((x^4 + 1) - 1)/(x(x^4 + 1))*dx`

= `int (1/x - 1/(x + x^5))*dx`

= log x – f(x) + c].

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Miscellaneous Exercise 3 [पृष्ठ १४८]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.02 | पृष्ठ १४८

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

If `int_(-pi/2)^(pi/2)sin^4x/(sin^4x+cos^4x)dx`, then the value of I is:

(A) 0

(B) π

(C) π/2

(D) π/4


Integrate the function in x sin 3x.


Integrate the function in x sin−1 x.


Integrate the function in x tan-1 x.


Integrate the function in x sec2 x.


Integrate the function in `e^x (1/x - 1/x^2)`.


`int e^x sec x (1 +   tan x) dx` equals:


Evaluate the following:

`int x^2 sin 3x  dx`


Evaluate the following : `int x^3.tan^-1x.dx`


Evaluate the following:

`int sec^3x.dx`


Evaluate the following : `int x.sin^2x.dx`


Evaluate the following : `int sin θ.log (cos θ).dθ`


Evaluate the following : `int(sin(logx)^2)/x.log.x.dx`


Evaluate the following : `int cos(root(3)(x)).dx`


Integrate the following functions w.r.t. x : `(x + 1) sqrt(2x^2 + 3)`


Integrate the following functions w.r.t. x : `sqrt(2x^2 + 3x + 4)`


Integrate the following functions w.r.t. x : [2 + cot x – cosec2x]e 


Integrate the following functions w.r.t. x : `e^x/x [x (logx)^2 + 2 (logx)]`


Choose the correct options from the given alternatives :

`int (log (3x))/(xlog (9x))*dx` =


Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =


Integrate the following with respect to the respective variable : `(sin^6θ + cos^6θ)/(sin^2θ*cos^2θ)`


Integrate the following w.r.t.x : `(1)/(x^3 sqrt(x^2 - 1)`


`int ("x" + 1/"x")^3 "dx"` = ______


Evaluate: Find the primitive of `1/(1 + "e"^"x")`


`int 1/(4x + 5x^(-11))  "d"x`


`int (cos2x)/(sin^2x cos^2x)  "d"x`


`int ("d"x)/(x - x^2)` = ______


`int 1/(x^2 - "a"^2)  "d"x` = ______ + c


`int (x^2 + x - 6)/((x - 2)(x - 1))  "d"x` = x + ______ + c


`int [(log x - 1)/(1 + (log x)^2)]^2`dx = ?


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


`int(logx)^2dx` equals ______.


Find `int e^(cot^-1x) ((1 - x + x^2)/(1 + x^2))dx`.


`int1/sqrt(x^2 - a^2) dx` = ______


`int logx  dx = x(1+logx)+c`


Evaluate the following.

`int (x^3)/(sqrt(1 + x^4))dx`


Prove that `int sqrt(x^2 - a^2)dx = x/2 sqrt(x^2 - a^2) - a^2/2 log(x + sqrt(x^2 - a^2)) + c`


The value of `int e^x((1 + sinx)/(1 + cosx))dx` is ______.


Evaluate `int tan^-1x  dx`


Evaluate:

`int1/(x^2 + 25)dx`


Evaluate:

`int x^2 cos x  dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)`dx


Evaluate:

`inte^x "cosec"  x(1 - cot x)dx`


Evaluate.

`int(5x^2 - 6x + 3)/(2x - 3)  dx`


The value of `int (x sin^-1)/(sqrt(1 - x^2)) dx` is equal to:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×