हिंदी

Integrate the following functions w.r.t. x : x2.a2-x6

Advertisements
Advertisements

प्रश्न

Integrate the following functions w.r.t. x : `x^2 .sqrt(a^2 - x^6)`

योग
Advertisements

उत्तर

Let I = `int x^2 .sqrt(a^2 - x^6).dx`

Put x3 = t
∴ 3x2.dx = dt

∴ x2dx = `(1)/(3).dt`

∴ I = `int sqrt(a^2 - t^2).dt/(3) = (1)/(3) int sqrt(a^2 - t^2).dt`

= `(1)/(3)[t/2 sqrt(a^2 - t^2) + a^2/(2) sin^-1 (t/a)] + c`

= `(1)/(6)[x^3 sqrt(a^2 - x^6) + a^2sin^-1 (x^3/a)] + c`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.3 [पृष्ठ १३८]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.3 | Q 2.05 | पृष्ठ १३८

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Prove that: `int sqrt(a^2 - x^2) * dx = x/2 * sqrt(a^2 - x^2) + a^2/2 * sin^-1(x/a) + c`


Integrate the function in x sin 3x.


Integrate the function in x sin−1 x.


Integrate the function in x cos-1 x.


Integrate the function in `sin^(-1) ((2x)/(1+x^2))`.


`int e^x sec x (1 +   tan x) dx` equals:


Evaluate the following : `int x^2.log x.dx`


Evaluate the following:

`int sec^3x.dx`


Evaluate the following:

`int x.sin 2x. cos 5x.dx`


Integrate the following functions w.r.t.x:

`e^-x cos2x`


Integrate the following functions w.r.t. x : `sqrt(5x^2 + 3)`


Integrate the following functions w.r.t. x : `sqrt(4^x(4^x + 4))`


Integrate the following functions w.r.t. x : `xsqrt(5 - 4x - x^2)`


Integrate the following functions w.r.t. x : `((1 + sin x)/(1 + cos x)).e^x`


Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`


Integrate the following functions w.r.t. x : `log(1 + x)^((1 + x)`


Integrate the following with respect to the respective variable : `t^3/(t + 1)^2`


Integrate the following w.r.t.x : `log (1 + cosx) - xtan(x/2)`


Integrate the following w.r.t.x : log (x2 + 1)


Evaluate the following.

`int x^3 e^(x^2)`dx


Evaluate the following.

`int [1/(log "x") - 1/(log "x")^2]` dx


Evaluate: `int "dx"/sqrt(4"x"^2 - 5)`


Evaluate: `int "dx"/(3 - 2"x" - "x"^2)`


Evaluate: `int "dx"/("9x"^2 - 25)`


`int (sinx)/(1 + sin x)  "d"x`


`int 1/(4x + 5x^(-11))  "d"x`


`int 1/(x^2 - "a"^2)  "d"x` = ______ + c


Evaluate `int 1/(4x^2 - 1)  "d"x`


`int log x * [log ("e"x)]^-2` dx = ?


`int "e"^x int [(2 - sin 2x)/(1 - cos 2x)]`dx = ______.


`int tan^-1 sqrt(x)  "d"x` is equal to ______.


If `int(2e^(5x) + e^(4x) - 4e^(3x) + 4e^(2x) + 2e^x)/((e^(2x) + 4)(e^(2x) - 1)^2)dx = tan^-1(e^x/a) - 1/(b(e^(2x) - 1)) + C`, where C is constant of integration, then value of a + b is equal to ______.


The integral `int x cos^-1 ((1 - x^2)/(1 + x^2))dx (x > 0)` is equal to ______.


Find `int (sin^-1x)/(1 - x^2)^(3//2) dx`.


Evaluate `int(1 + x + (x^2)/(2!))dx`


Evaluate:

`intcos^-1(sqrt(x))dx`


Evaluate:

`int e^(logcosx)dx`


Prove that `int sqrt(x^2 - a^2)dx = x/2 sqrt(x^2 - a^2) - a^2/2 log(x + sqrt(x^2 - a^2)) + c`


Complete the following activity:

`int_0^2 dx/(4 + x - x^2) `

= `int_0^2 dx/(-x^2 + square + square)`

= `int_0^2 dx/(-x^2 + x + 1/4 - square + 4)`

= `int_0^2 dx/ ((x- 1/2)^2 - (square)^2)`

= `1/sqrt17 log((20 + 4sqrt17)/(20 - 4sqrt17))`


Evaluate the following:

`intx^3e^(x^2)dx` 


Evaluate `int (1 + x + x^2/(2!))dx`


If f′(x) = 4x3 − 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate the following.

`intx^2e^(4x)dx`


The value of `inta^x.e^x dx` equals


Evaluate the following.

`intx^3 e^(x^2)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×