हिंदी

Integrate the following functions w.r.t.x: e5x.[5x.logx+1x]

Advertisements
Advertisements

प्रश्न

Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`

योग
Advertisements

उत्तर

Let I = `int e^(5x) [(5x.log x + 1)/x].dx`

= `int e^(5x)[5log x + 1/x].dx`

Put 5x = t

∴ 5.dx = dt

∴ dx = `(1)/(5).dt`

Also, x = `t/(5)`

∴ I = `(1)/(5) int e^t [5 log (t/5) + 5/t].dt`

Let f(t) = `5log (t/5)`

= 5 log t – 5 log 5

∴ f'(t) = `d/dt [5log t - 5 log 5]`

= `(5)/t - 0`

= `(5)/t`

∴ I = `(1)/(5) int e^t [f(t) + f^'(t)].dt`

= `(1)/(5) e^t f(t) + c`

= `(1)/(5) e^t . 5log (t/5) + c`

=  e5x log x + c.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.3 [पृष्ठ १३८]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.3 | Q 3.6 | पृष्ठ १३८

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Prove that: `int sqrt(a^2 - x^2) * dx = x/2 * sqrt(a^2 - x^2) + a^2/2 * sin^-1(x/a) + c`


Integrate the function in (sin-1x)2.


Integrate the function in `(x cos^(-1) x)/sqrt(1-x^2)`.


Evaluate the following : `int x^2tan^-1x.dx`


Evaluate the following : `int x.sin^2x.dx`


Evaluate the following : `int log(logx)/x.dx`


Integrate the following functions w.r.t.x:

`e^-x cos2x`


Choose the correct options from the given alternatives :

`int (log (3x))/(xlog (9x))*dx` =


Choose the correct options from the given alternatives :

`int sin (log x)*dx` =


Integrate the following with respect to the respective variable : `(sin^6θ + cos^6θ)/(sin^2θ*cos^2θ)`


Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`


Integrate the following w.r.t.x : e2x sin x cos x


Integrate the following w.r.t.x : sec4x cosec2x


Evaluate the following.

`int x^2 *e^(3x)`dx


Evaluate the following.

`int "e"^"x" "x"/("x + 1")^2` dx


Evaluate the following.

`int [1/(log "x") - 1/(log "x")^2]` dx


Choose the correct alternative from the following.

`int (("x"^3 + 3"x"^2 + 3"x" + 1))/("x + 1")^5  "dx"` = 


Evaluate: Find the primitive of `1/(1 + "e"^"x")`


Evaluate: `int "dx"/(5 - 16"x"^2)`


Evaluate:

∫ (log x)2 dx


`int (sinx)/(1 + sin x)  "d"x`


`int (cos2x)/(sin^2x cos^2x)  "d"x`


`int sin4x cos3x  "d"x`


Evaluate `int (2x + 1)/((x + 1)(x - 2))  "d"x`


`int 1/sqrt(x^2 - 8x - 20)  "d"x`


`int "dx"/(sin(x - "a")sin(x - "b"))` is equal to ______.


The value of `int_(- pi/2)^(pi/2) (x^3 + x cos x + tan^5x + 1)  dx` is


The value of `int_0^(pi/2) log ((4 + 3 sin x)/(4 + 3 cos x))  dx` is


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


Evaluate: `int_0^(pi/4) (dx)/(1 + tanx)`


The integral `int x cos^-1 ((1 - x^2)/(1 + x^2))dx (x > 0)` is equal to ______.


If `π/2` < x < π, then `intxsqrt((1 + cos2x)/2)dx` = ______.


`int e^x [(2 + sin 2x)/(1 + cos 2x)]dx` = ______.


Evaluate: 

`int(1+logx)/(x(3+logx)(2+3logx))  dx`


`int1/(x+sqrt(x))  dx` = ______


`inte^(xloga).e^x dx` is ______


`int(xe^x)/((1+x)^2)  dx` = ______


Evaluate:

`intcos^-1(sqrt(x))dx`


Evaluate:

`int (logx)^2 dx`


`int (sin^-1 sqrt(x) + cos^-1 sqrt(x))dx` = ______.


Prove that `int sqrt(x^2 - a^2)dx = x/2 sqrt(x^2 - a^2) - a^2/2 log(x + sqrt(x^2 - a^2)) + c`


Evaluate `int tan^-1x  dx`


Evaluate the following.

`intx^3  e^(x^2) dx`


Evaluate the following.

`intx^3 e^(x^2) dx`


Evaluate the following.

`intx^3 e^(x^2)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×