हिंदी

Choose the correct alternative from the following. xxxx + 1dx∫(x3+3x2+3x+1)(x + 1)5 dx =

Advertisements
Advertisements

प्रश्न

Choose the correct alternative from the following.

`int (("x"^3 + 3"x"^2 + 3"x" + 1))/("x + 1")^5  "dx"` = 

विकल्प

  • `(-1)/"x + 1"` + c

  • `((-1)/"x + 1")^5` + c

  • log(x + 1) + c

  • log |x + 1|5 + c 

MCQ
Advertisements

उत्तर

`(-1)/"x + 1"` + c

Explanation:

= `int ("x + 1")^3/("x + 1")^5` dx

∵ (a + b)3 = a3 + 3a2b + 3ab2 + b3

(x + 1)3 = x3 + 3x2 + 3x + 1

= `1/((x + 1)^2) dx`

= `int (x + 1)^-2 . dx`

= `(x + 1)^(-2 + 1)/-2 + 1 + c`

= `(x + 1)^-1/-1 + c`

= `(-1)/(x + 1) + c`

`= (-1)/"x + 1"` + c

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Integration - MISCELLANEOUS EXERCISE - 5 [पृष्ठ १३८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 5 Integration
MISCELLANEOUS EXERCISE - 5 | Q I. 10) | पृष्ठ १३८

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

`int1/xlogxdx=...............`

(A)log(log x)+ c

(B) 1/2 (logx )2+c

(C) 2log x + c

(D) log x + c


If u and v are two functions of x then prove that

`intuvdx=uintvdx-int[du/dxintvdx]dx`

Hence evaluate, `int xe^xdx`


Integrate the function in x log 2x.


Integrate the function in x tan-1 x.


Integrate the function in x sec2 x.


Integrate the function in `e^x (1 + sin x)/(1+cos x)`.


Integrate the function in `((x- 3)e^x)/(x - 1)^3`.


Evaluate the following : `int x^3.tan^-1x.dx`


Evaluate the following : `int e^(2x).cos 3x.dx`


Choose the correct options from the given alternatives :

`int cos -(3)/(7)x*sin -(11)/(7)x*dx` =


Integrate the following with respect to the respective variable : `(sin^6θ + cos^6θ)/(sin^2θ*cos^2θ)`


Integrate the following w.r.t.x : `(1)/(xsin^2(logx)`


Integrate the following w.r.t.x : log (log x)+(log x)–2 


Evaluate the following.

∫ x log x dx


Evaluate:

∫ (log x)2 dx


`int 1/sqrt(2x^2 - 5)  "d"x`


`int sin4x cos3x  "d"x`


Choose the correct alternative:

`int ("d"x)/((x - 8)(x + 7))` =


`int "e"^x int [(2 - sin 2x)/(1 - cos 2x)]`dx = ______.


If u and v ore differentiable functions of x. then prove that:

`int uv  dx = u intv  dx - int [(du)/(d) intv  dx]dx`

Hence evaluate `intlog x  dx`


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


`int(3x^2)/sqrt(1+x^3) dx = sqrt(1+x^3)+c`


`int1/(x+sqrt(x))  dx` = ______


Evaluate `int(1 + x + (x^2)/(2!))dx`


Evaluate:

`int e^(ax)*cos(bx + c)dx`


Evaluate:

`int (logx)^2 dx`


Prove that `int sqrt(x^2 - a^2)dx = x/2 sqrt(x^2 - a^2) - a^2/2 log(x + sqrt(x^2 - a^2)) + c`


Evaluate:

`inte^x "cosec"  x(1 - cot x)dx`


Evaluate.

`int(5x^2 - 6x + 3)/(2x - 3)  dx`


Evaluate \[\int x\cos x\,dx.\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×