हिंदी

∫e4x-3dx = ______ + c - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

`int"e"^(4x - 3) "d"x` = ______ + c

रिक्त स्थान भरें
Advertisements

उत्तर

`int"e"^(4x - 3) "d"x` = `bbunderline(1/4e^(4x-3)` + c

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1.5: Integration - Q.2

संबंधित प्रश्न

If `int_(-pi/2)^(pi/2)sin^4x/(sin^4x+cos^4x)dx`, then the value of I is:

(A) 0

(B) π

(C) π/2

(D) π/4


If u and v are two functions of x then prove that

`intuvdx=uintvdx-int[du/dxintvdx]dx`

Hence evaluate, `int xe^xdx`


Evaluate `int_0^(pi)e^2x.sin(pi/4+x)dx`


Integrate the function in x sin 3x.


Integrate the function in `x^2e^x`.


Evaluate the following : `int x^3.logx.dx`


Evaluate the following : `int x.cos^3x.dx`


Evaluate the following:

`int x.sin 2x. cos 5x.dx`


Integrate the following functions w.r.t.x:

`e^-x cos2x`


Integrate the following functions w.r.t. x : `(x + 1) sqrt(2x^2 + 3)`


Integrate the following functions w.r.t. x : `sqrt(2x^2 + 3x + 4)`


Choose the correct options from the given alternatives :

`int tan(sin^-1 x)*dx` =


Choose the correct options from the given alternatives :

`int sin (log x)*dx` =


Evaluate the following.

`int e^x (1/x - 1/x^2)`dx


`int ("x" + 1/"x")^3 "dx"` = ______


Choose the correct alternative from the following.

`int (("x"^3 + 3"x"^2 + 3"x" + 1))/("x + 1")^5  "dx"` = 


Evaluate: `int "dx"/(3 - 2"x" - "x"^2)`


`int (cos2x)/(sin^2x cos^2x)  "d"x`


`int 1/sqrt(x^2 - 8x - 20)  "d"x`


If u and v ore differentiable functions of x. then prove that:

`int uv  dx = u intv  dx - int [(du)/(d) intv  dx]dx`

Hence evaluate `intlog x  dx`


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


Find the general solution of the differential equation: `e^((dy)/(dx)) = x^2`.


Find `int e^x ((1 - sinx)/(1 - cosx))dx`.


`int(3x^2)/sqrt(1+x^3) dx = sqrt(1+x^3)+c`


Evaluate the following:

`intx^3e^(x^2)dx` 


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)


Evaluate the following.

`intx^2e^(4x)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×