हिंदी

Integrate the following functions w.r.t. x: sin (log x) - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Integrate the following functions w.r.t. x:

sin (log x)

योग
Advertisements

उत्तर

Le I  = `int sin (logx)x dx`

Put log x = t
∴ x = et
∴ dx = et dt

∴ I = `int sin t xx e^t dt`

= `int e^t sin t dt`

= `e^t int sin t dt - int [d/dt (e^t) int sin t dt] dt`

= `e^t (- cos t) - int e^t (- cos t) dt`

= `-e^t cos t + int e^t cos t dt`

= `- e^t cos t + e^t int cos t dt - int [d/dt (e^t) int cos t dt] dt`

= `- e^t cos t + e^t sin t - int e^t sin t dt`

∴ I = – et cos t + et sin t – I
∴ 2I = et (sin t – cos t)

∴ `I  = e^t/(2) (sin t - cos t) + c`

= `x/(2) [sin (logx) - cos (logx)] + c`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.3 [पृष्ठ १३८]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.3 | Q 2.03 | पृष्ठ १३८

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

If `int_(-pi/2)^(pi/2)sin^4x/(sin^4x+cos^4x)dx`, then the value of I is:

(A) 0

(B) π

(C) π/2

(D) π/4


Integrate the function in x sin 3x.


Integrate the function in `x^2e^x`.


Integrate the function in x log 2x.


Integrate the function in x sin−1 x.


Integrate the function in e2x sin x.


Find : 

`∫(log x)^2 dx`


Evaluate the following:

`int sec^3x.dx`


Integrate the following functions w.r.t.x:

`e^-x cos2x`


Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`


Integrate the following functions w.r.t. x : cosec (log x)[1 – cot (log x)] 


Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =


Choose the correct options from the given alternatives :

`int (1)/(cosx - cos^2x)*dx` =


Choose the correct options from the given alternatives :

`int sin (log x)*dx` =


Choose the correct options from the given alternatives :

`int cos -(3)/(7)x*sin -(11)/(7)x*dx` =


Integrate the following w.r.t.x : `log (1 + cosx) - xtan(x/2)`


Evaluate the following.

∫ x log x dx


Evaluate the following.

`int x^2 e^4x`dx


Evaluate the following.

`int e^x (1/x - 1/x^2)`dx


Evaluate the following.

`int [1/(log "x") - 1/(log "x")^2]` dx


Choose the correct alternative from the following.

`int (("e"^"2x" + "e"^"-2x")/"e"^"x") "dx"` = 


Choose the correct alternative from the following.

`int (1 - "x")^(-2) "dx"` = 


Evaluate: `int "dx"/("9x"^2 - 25)`


Evaluate: `int "dx"/(5 - 16"x"^2)`


Evaluate: `int "dx"/(25"x" - "x"(log "x")^2)`


`int (sinx)/(1 + sin x)  "d"x`


`int ["cosec"(logx)][1 - cot(logx)]  "d"x`


`int(x + 1/x)^3 dx` = ______.


Evaluate `int 1/(x log x)  "d"x`


Evaluate `int 1/(4x^2 - 1)  "d"x`


Evaluate `int (2x + 1)/((x + 1)(x - 2))  "d"x`


`int "e"^x x/(x + 1)^2  "d"x`


`int log x * [log ("e"x)]^-2` dx = ?


The value of `int "e"^(5x) (1/x - 1/(5x^2))  "d"x` is ______.


Find `int_0^1 x(tan^-1x)  "d"x`


Evaluate the following:

`int_0^pi x log sin x "d"x`


`int "dx"/(sin(x - "a")sin(x - "b"))` is equal to ______.


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


Find: `int e^x.sin2xdx`


Solve: `int sqrt(4x^2 + 5)dx`


Evaluate :

`int(4x - 6)/(x^2 - 3x + 5)^(3/2)  dx`


`int(1-x)^-2 dx` = ______


Evaluate:

`intcos^-1(sqrt(x))dx`


Evaluate:

`inte^x sinx  dx`


Evaluate:

`int (logx)^2 dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)


Evaluate the following. 

`int x sqrt(1 + x^2)  dx`  


Evaluate the following.

`int x^3 e^(x^2) dx` 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×