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प्रश्न
Integrate the function in x sec2 x.
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उत्तर
Let `I = int x sec^2 x dx`
Put `u = x, v = sec^2 x`
`therefore int uv dx = u int v dx - int ((du)/dx int v dx) dx`
`= x int sec^2 x dx - int [(d(x))/dx int sec^2 x dx] dx`
`= x tan x - int 1. tan x dx`
`= x tan x + log abs (cos x) + C`
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