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Evaluate: ∫ x tan^-1 x dx

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प्रश्न

Evaluate the following:

`int x tan^-1 x . dx`

Evaluate:

∫ x tan-1 x dx

मूल्यांकन
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उत्तर

Let I = `int x tan^-1 x  .  dx`

= `int (tan^-1 x)x  .  dx`

= `(tan^-1 x) int x  .  dx - int[{d/dx(tan^-1 x) intx.dx}]  .  dx`

= `(tan^-1x) (x^2/2) - int (1/(1 + x^2)) (x^2/2)  .  dx`

= `(x^2 tan^-1)/(2) - (1)/(2) int x^2/(x^2 + 1)  .  dx`

= `x^2/(2) tan^-1x - (1)/(2) ((x^2 + 1)-1)/(x^2 + 1)  ⋅  dx`

= `x^2/(2)tan^-1x - (1)/(2)[int(1 - 1/(x^2 + 1))  ⋅  dx]`

= `x^2/(2)tan^-1x - (1)/(2)[int 1  .  dx - int(1)/(x^2 + 1)  .  dx]`

= `x^2/(2)tan^-1 x - (1)/(2)(x - tan^-1x) + c`.

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अध्याय 3: Indefinite Integration - Exercise 3.3 [पृष्ठ १३७]

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