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Integrate the function in tan-1 x.

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प्रश्न

Integrate the function in tan-1 x.

योग
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उत्तर

Let `I = int tan^-1 x  dx`

`= int tan^-1 x. 1  dx`

Put `u = tan^-1 x, v = 1` 

`int uv  dx = u int v  dx - int ((du)/dx int v  dx)  dx`

`I= int tan^-1 x. 1`

`(tan^-1 x) int 1  dx - (d/dx (tan^-1 x) int dx) dx`

`= x tan^-1 x - int 1/(1 + x^2) . x  dx`

`= x tan^-1 x - 1/2 int (2x)/(1 + x^2)  dx`

Put 1 + x2 = t, and dx = dt

`= x tan^-1 x - 1/2 int dt/t`

`= x tan^-1 x - 1/2  log t + C`

`= x tan^1 - 1/2  log (1 + x^2) + C`

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अध्याय 7: Integrals - Exercise 7.6 [पृष्ठ ३२७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.6 | Q 13 | पृष्ठ ३२७

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