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Integrate the function in x (log x)2.

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प्रश्न

Integrate the function in x (log x)2.

योग
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उत्तर

Let `I = int x (log x)^2 dx`

`= int (log x)^2 * x dx`

`= (log x)^2 int x  dx - int [d/dx (log x)^2 * int x  dx] dx`

`= x^2/2 (log x)^2 - int (log x) * x dx + C`

`= x^2/2 (log x)^2 - [ (log x) * x^2/2 - int 1/x * x^2/2 dx]`

`= x^2/2 (log x)^2 - x^2/2 log x  + 1/2 int x  dx`

`= x^2/2 (log x)^2 - x^2/2 log x + 1/2 int*x^2/2 + C`

`= x^2 (log x)^2 - x^2/2 log x + 1/2 * x^2/2 + C`

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अध्याय 7: Integrals - Exercise 7.6 [पृष्ठ ३२७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.6 | Q 14 | पृष्ठ ३२७

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