Advertisements
Advertisements
प्रश्न
Integrate the following w.r.t.x : cot–1 (1 – x + x2)
Advertisements
उत्तर
Let I = `int cot^-1 (1 - x + x^2)*dx`
= `int tan^-1 (1/(1 - x + x^2))*dx`
= `int tan^-1 [(x + (1 - x))/(1 - x(1 - x))]`
= `int [tan^-1 x + tan^-1 (1 - x)]*dx`
= `int tan^-1 x*dx + int tan^-1 (1 - x)*dx`
∴ I = I1 + I2 ...(1)
I1 = `int tan^-1 x*dx = int(tan^-1x)1*dx`
= `(tan^-1x)* int 1dx - [d/dx (tan^-1x)* int 1dx]*dx`
= `(tan^-1x)x - int 1/(1 + x^2)*x*dx`
= `xtan^-1 x - (1)/(2) int (2x)/(1 + x^2)*dx`
∴ I1 = `x tan^-1x - (1)/(2)log|1 + x^2| + c_1`
...`[because d/dx (1 + x^2) = 2x and int (f'(x))/f(x) dx = log|f(x)| + c]`
I2 = `int tan^-1 (1 - x)*dx`
= `int tan^-1 (1 - x)]*1dx`
= `[tan^-1 (1 - x)]*int 1dx - int {d/dx [tan^-1 (1 - x)]* int 1dx}*dx`
= `[tan^-1 (1 - x)]*x - int (1)/(1 + (1 - x)^2)*(-1)*xdx`
= `xtan^-1 (1 - x) + int x/(1 + 1 - 2x + x^2)*dx`
= `xtan^-1 (1 - x) + int x/(2 - 2x + x^2)*dx`
Let x = `"A"[d/dx (2 - 2x + x^2)] + "B"`
∴ x = A(– 2 + 2x) + B = 2Ax + (–2A + B)
Comparing the coefficient of x and constant on both the sides, we get
1 = 2A and 0 = – 2A + B
∴ A = `(1)/(2) and 0 = -2(1/2) + "B"`
∴ B = 1
∴ x = `(1)/(2)(- 2 + 2x) + 1`
∴ I2= `xtan^-1 (1 - x) + int (1/2(-2 + 2x) + 1)/(2 - 2x + x^2)*dx`
= `xtan^-1 (1 - x) + 1/2 (-2 + 2x)/(2 - 2x + x^2)*dx + int (1)/(2 - 2x + x^2)*dx`
= `xtan^-1 (1 - x) + (1)/(2) log|2 - 2x + x^2| + int (1)/(1 + (1 - 2x + x^2))*dx`
= `xtan^-1 (1 - x) + (1)/(2) log|x^2 - 2x + 2| + int (1)/(1 + (1 - x^2))*dx`
= `xtan^-1 (1 - x) + (1)/(2) log|x^2 - 2x + 2| + (1)/(1) (tan-1 (1 - x))/(-1) + c_2`
= `x tan^-1 (1 - x) + 1/2log|x^2 - 2x + 2| - tan^-1 (1 - x) + c_2`
= `(x - 1)tan^-1 (1 - x) + (1)/(2)log|x^2 - 2x + 2| + c_2`
∴ I2 = `-(1 - x)tan^-1 (1 - x) + (1)/(2)log|x^2 - 2x + 2| + c_2` ...(3)
From (1),(2) and (3), we get
I = `x tan^-1 x - (1)/(2) log|1 + x^2| + c_1 - (1 - x)tan^-1 (1 - x) + 1/2log|x^2 - 2x + 2| + c_2`
= `x tan^-1 x - (1)/(2) log|1 + x^2| - (1 - x)tan^-1 (1 - x) + 1/2 |x^2 - 2x + 2| + c`, where c = c1 + c2.
APPEARS IN
संबंधित प्रश्न
Prove that:
`int sqrt(x^2 - a^2)dx = x/2sqrt(x^2 - a^2) - a^2/2log|x + sqrt(x^2 - a^2)| + c`
Integrate the function in x2 log x.
Integrate the function in x sin−1 x.
Integrate the function in (sin-1x)2.
Integrate the function in x (log x)2.
Integrate the function in `(xe^x)/(1+x)^2`.
Integrate the function in e2x sin x.
Evaluate the following : `int x^2tan^-1x.dx`
Evaluate the following: `int x.sin^-1 x.dx`
Evaluate the following : `int cos sqrt(x).dx`
Evaluate the following : `int sin θ.log (cos θ).dθ`
Integrate the following functions w.r.t. x : `(x + 1) sqrt(2x^2 + 3)`
Integrate the following functions w.r.t. x : `sqrt(2x^2 + 3x + 4)`
Choose the correct options from the given alternatives :
`int (1)/(x + x^5)*dx` = f(x) + c, then `int x^4/(x + x^5)*dx` =
Choose the correct options from the given alternatives :
`int (log (3x))/(xlog (9x))*dx` =
Choose the correct options from the given alternatives :
`int tan(sin^-1 x)*dx` =
Integrate the following with respect to the respective variable : `(3 - 2sinx)/(cos^2x)`
Integrate the following w.r.t.x : `(1)/(xsin^2(logx)`
Integrate the following w.r.t.x : log (log x)+(log x)–2
Evaluate the following.
`int "e"^"x" [(log "x")^2 + (2 log "x")/"x"]` dx
Evaluate: `int "dx"/(25"x" - "x"(log "x")^2)`
`int ["cosec"(logx)][1 - cot(logx)] "d"x`
`int sin4x cos3x "d"x`
Choose the correct alternative:
`intx^(2)3^(x^3) "d"x` =
`int"e"^(4x - 3) "d"x` = ______ + c
`int (x^2 + x - 6)/((x - 2)(x - 1)) "d"x` = x + ______ + c
State whether the following statement is True or False:
If `int((x - 1)"d"x)/((x + 1)(x - 2))` = A log|x + 1| + B log|x – 2|, then A + B = 1
`int "e"^x x/(x + 1)^2 "d"x`
∫ log x · (log x + 2) dx = ?
Evaluate the following:
`int ((cos 5x + cos 4x))/(1 - 2 cos 3x) "d"x`
`int "dx"/(sin(x - "a")sin(x - "b"))` is equal to ______.
`int tan^-1 sqrt(x) "d"x` is equal to ______.
`int 1/sqrt(x^2 - 9) dx` = ______.
State whether the following statement is true or false.
If `int (4e^x - 25)/(2e^x - 5)` dx = Ax – 3 log |2ex – 5| + c, where c is the constant of integration, then A = 5.
`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`
Find `int (sin^-1x)/(1 - x^2)^(3//2) dx`.
Evaluate :
`int(4x - 6)/(x^2 - 3x + 5)^(3/2) dx`
`intsqrt(1+x) dx` = ______
`int(3x^2)/sqrt(1+x^3) dx = sqrt(1+x^3)+c`
Evaluate:
`intcos^-1(sqrt(x))dx`
Evaluate:
`int((1 + sinx)/(1 + cosx))e^x dx`
Evaluate:
`inte^x sinx dx`
Evaluate the following.
`intx^3 e^(x^2) dx`
Evaluate:
`int x^2 cos x dx`
Evaluate the following.
`int x^3 e^(x^2) dx`
Integration by parts is a method of integration based on which rule of differentiation?
Which pair is listed as Trigonometric in the LIATE rule?
