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प्रश्न
Integrate the function in x sin−1 x.
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उत्तर
Let `I = int x sin^-1 x dx = int sin^-1 x* x dx`
`= sin^-1 x* (x^2/2) - int [d/dx (sin^-1 x) * x^2/2] dx`
`= sin^-1 x (x^2/2) - int 1/sqrt (1 - x^2)* x^2/2 dx`
`= x^2/2 sin^-1 x - 1/2 int x^2/ sqrt (1 - x^2) dx`
`= x^2/2 sin^-1 x - 1/2 I_1`
`I = x^2/2 sin^-1 x - 1/2 I_1` ....(i)
Where `I_1 = int x^2/sqrt (1 - x^2) dx`
Put x = sin θ
⇒ dx = cosθ dθ
∴ `I_1 = int (sin^2 theta)/sqrt (1- sin^2 theta) cos d theta`
`= int (sin^2 theta)/(cos theta) * cos theta d theta`
`= int sin^2 theta d theta = 1/2 int (1 - cos 2 theta) d theta`
`= 1/2int d theta - 1/2 int cos 2 theta d theta 1/2 theta - 1/2 (sin 2 theta)/2 + C`
`1/2 theta - 1/2 sin theta cos theta + C`
`1/2 sin^-1x - 1/2x sqrt(1 - x^2) + C` ....(ii)
`[∵ sin theta = x ⇒ cos theta = sqrt (1 - sin^2 theta) = sqrt (1 - x^2)]`
From (i) and (ii), we get
∴ `I = x^2/2 sin^-1 x - 1/2 [1/2 sin^-1 x - 1/2 x sqrt(1 - x^2)] + C`
`= 1/4 sin^-1 x* (2x^2 - 1) + (x sqrt (1 - x^2))/4 + C`
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