हिंदी

Integrate the following w.r.t.x : xsec(x32)⋅tan(x32)

Advertisements
Advertisements

प्रश्न

Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`

योग
Advertisements

उत्तर

Let I = `int sqrt(x)sec(x^(3/2))*tan(x^(3/2))`

Put `x^(3/2)` = t

∴ `(3)/(2) sqrt(x)*dx` = dt

∴ `sqrt(x)*dx = (2)/(3)*dt`

∴ I = `(2)/(3) int sec t tan t*dt`

= `(2)/(3)sec t + c`

= `(2)/(3) sec(x^(3/2)) + c`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Miscellaneous Exercise 3 [पृष्ठ १५०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 3.04 | पृष्ठ १५०

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Integrate the function in xlog x.


Integrate the function in x sec2 x.


Integrate the function in tan-1 x.


Integrate the function in ex (sinx + cosx).


Find : 

`∫(log x)^2 dx`


Evaluate the following:

`int x tan^-1 x . dx`


Evaluate the following : `int x^3.tan^-1x.dx`


Evaluate the following:

`int sec^3x.dx`


Evaluate the following : `int (t.sin^-1 t)/sqrt(1 - t^2).dt`


Evaluate the following:

`int x.sin 2x. cos 5x.dx`


Integrate the following functions w.r.t. x : `sqrt(2x^2 + 3x + 4)`


Integrate the following functions w.r.t. x : `((1 + sin x)/(1 + cos x)).e^x`


Integrate the following functions w.r.t. x : `e^x/x [x (logx)^2 + 2 (logx)]`


Integrate the following functions w.r.t. x : `e^(sin^-1x)*[(x + sqrt(1 - x^2))/sqrt(1 - x^2)]`


Integrate the following functions w.r.t. x : cosec (log x)[1 – cot (log x)] 


Choose the correct options from the given alternatives :

`int cos -(3)/(7)x*sin -(11)/(7)x*dx` =


Integrate the following with respect to the respective variable : `(sin^6θ + cos^6θ)/(sin^2θ*cos^2θ)`


Integrate the following w.r.t. x: `(1 + log x)^2/x`


Integrate the following w.r.t.x : log (x2 + 1)


Evaluate the following.

`int x^2 *e^(3x)`dx


Evaluate the following.

`int (log "x")/(1 + log "x")^2` dx


Choose the correct alternative from the following.

`int (("e"^"2x" + "e"^"-2x")/"e"^"x") "dx"` = 


Evaluate: `int "dx"/(25"x" - "x"(log "x")^2)`


Evaluate `int 1/(4x^2 - 1)  "d"x`


Evaluate `int (2x + 1)/((x + 1)(x - 2))  "d"x`


`int "e"^x x/(x + 1)^2  "d"x`


∫ log x · (log x + 2) dx = ?


`int log x * [log ("e"x)]^-2` dx = ?


Find `int_0^1 x(tan^-1x)  "d"x`


Evaluate: `int_0^(pi/4) (dx)/(1 + tanx)`


`int 1/sqrt(x^2 - a^2)dx` = ______.


The integral `int x cos^-1 ((1 - x^2)/(1 + x^2))dx (x > 0)` is equal to ______.


Find: `int e^(x^2) (x^5 + 2x^3)dx`.


Evaluate :

`int(4x - 6)/(x^2 - 3x + 5)^(3/2)  dx`


`int logx  dx = x(1+logx)+c`


`int(f'(x))/sqrt(f(x)) dx = 2sqrt(f(x))+c`


Solve the following

`int_0^1 e^(x^2) x^3 dx`


Evaluate:

`intcos^-1(sqrt(x))dx`


Evaluate:

`int((1 + sinx)/(1 + cosx))e^x dx`


Evaluate:

`int e^(logcosx)dx`


Evaluate:

`int1/(x^2 + 25)dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)`dx


Evaluate:

`inte^x "cosec"  x(1 - cot x)dx`


Which expression is the integration-by-parts form for a product \(f(x)g(x)\)?


For \[\int \frac{x\sin^{-1}x}{\sqrt{1-x^2}}\,dx,\] which functions are chosen as the first function and the second function?


Which substitution can also be used before integrating by parts for \[\int \frac{x\sin^{-1}x}{\sqrt{1-x^2}}\,dx?\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×