हिंदी

Evaluate the following. ∫𝑥2 ⋅𝑒3⁢𝑥dx

Advertisements
Advertisements

प्रश्न

Evaluate the following.

`int x^2 *e^(3x)`dx

मूल्यांकन
Advertisements

उत्तर

Let I = `int x^2 e^(3x)`dx

`= x^2 int e^(3x)  dx - int[d/dx (x^2) int e^(3x) dx]` dx

`= x^2 * (e^(3x)/3) - int 2x * e^(3x)/3` dx

`= (x^2)/3  e^(3x) - 2/3 int x * e^(3x)` dx

`= (x^2)/3  e^(3x) - 2/3 [x int e^(3x)  dx - int (d/dx (x) int e^(3x) dx) dx]`

`= (x^2 * e^(3x))/3 - 2/3 [x * e^(3x)/3 - int 1 * e^(3x)/3  dx]`

`= (x^2 * e^(3x))/3 - 2/3 [1/3 xe^(3x) - 1/3 int e^(3x)  dx]`

`= (x^2 * e^(3x))/3 - 2/3 [1/3 xe^(3x) - 1/3 * e^(3x)/3]` + c

∴ I = `1/3 x^2 * e^(3x) - 2/9 xe^(3x) + 2/27 e^(3x) + c`

shaalaa.com

Notes

The answer in the textbook is incorrect.

  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Integration - EXERCISE 5.5 [पृष्ठ १३३]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 5 Integration
EXERCISE 5.5 | Q 3) | पृष्ठ १३३

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Prove that: `int sqrt(a^2 - x^2) * dx = x/2 * sqrt(a^2 - x^2) + a^2/2 * sin^-1(x/a) + c`


Integrate the function in x log 2x.


Integrate the function in tan-1 x.


Integrate the function in (x2 + 1) log x.


Integrate the function in `((x- 3)e^x)/(x - 1)^3`.


`intx^2 e^(x^3) dx` equals: 


Evaluate the following : `int x^2tan^-1x.dx`


Evaluate the following : `int sin θ.log (cos θ).dθ`


Choose the correct options from the given alternatives :

`int (1)/(x + x^5)*dx` = f(x) + c, then `int x^4/(x + x^5)*dx` =


Choose the correct options from the given alternatives :

`int tan(sin^-1 x)*dx` =


Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =


Integrate the following w.r.t.x : `(1)/(x^3 sqrt(x^2 - 1)`


Integrate the following w.r.t.x : e2x sin x cos x


Evaluate the following.

`int "e"^"x" [(log "x")^2 + (2 log "x")/"x"]` dx


Choose the correct alternative from the following.

`int (1 - "x")^(-2) "dx"` = 


`int (cos2x)/(sin^2x cos^2x)  "d"x`


Choose the correct alternative:

`int ("d"x)/((x - 8)(x + 7))` =


`int(x + 1/x)^3 dx` = ______.


`int 1/x  "d"x` = ______ + c


`int 1/sqrt(x^2 - a^2)dx` = ______.


Solve: `int sqrt(4x^2 + 5)dx`


`int(1-x)^-2 dx` = ______


`int1/sqrt(x^2 - a^2) dx` = ______


Solve the differential equation (x2 + y2) dx - 2xy dy = 0 by completing the following activity.

Solution: (x2 + y2) dx - 2xy dy = 0

∴ `dy/dx=(x^2+y^2)/(2xy)`                      ...(1)

Puty = vx

∴ `dy/dx=square`

∴ equation (1) becomes

`x(dv)/dx = square`

∴ `square  dv = dx/x`

On integrating, we get

`int(2v)/(1-v^2) dv =intdx/x`

∴ `-log|1-v^2|=log|x|+c_1`

∴ `log|x| + log|1-v^2|=logc       ...["where" - c_1 = log c]`

∴ x(1 - v2) = c

By putting the value of v, the general solution of the D.E. is `square`= cx


`int (sin^-1 sqrt(x) + cos^-1 sqrt(x))dx` = ______.


Evaluate the following.

`intx^3  e^(x^2) dx`


Evaluate:

`inte^x "cosec"  x(1 - cot x)dx`


Which expression is the integration-by-parts form for a product \(f(x)g(x)\)?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×