हिंदी

Evaluate the following: ∫log⁡𝑥𝑥.𝑑⁢𝑥

Advertisements
Advertisements

प्रश्न

Evaluate the following: `int logx/x.dx`

योग
Advertisements

उत्तर

Let I = `int logx/x.dx`

Put log x = t       

∴ `(1)/x.dx` = dt

∴ I = `int t.dt`

= `t^2/(2) + c`

= `(logx)^2/(2) + c`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.3 [पृष्ठ १३७]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.3 | Q 1.19 | पृष्ठ १३७

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Prove that:

`int sqrt(x^2 - a^2)dx = x/2sqrt(x^2 - a^2) - a^2/2log|x + sqrt(x^2 - a^2)| + c`


Integrate the function in x sin 3x.


Integrate the function in x log 2x.


Integrate the function in xlog x.


Integrate the function in (sin-1x)2.


Prove that:

`int sqrt(x^2 + a^2)dx = x/2 sqrt(x^2 + a^2) + a^2/2 log |x + sqrt(x^2 + a^2)| + c`


Find : 

`∫(log x)^2 dx`


Evaluate the following : `int x^2.log x.dx`


Evaluate the following : `int x.sin^2x.dx`


Evaluate the following : `int x^2*cos^-1 x*dx`


Evaluate the following : `int log(logx)/x.dx`


Evaluate the following : `int cos sqrt(x).dx`


Evaluate the following : `int(sin(logx)^2)/x.log.x.dx`


Integrate the following functions w.r.t. x : cosec (log x)[1 – cot (log x)] 


Choose the correct options from the given alternatives :

`int (log (3x))/(xlog (9x))*dx` =


Choose the correct options from the given alternatives :

`int sin (log x)*dx` =


Choose the correct options from the given alternatives :

`int cos -(3)/(7)x*sin -(11)/(7)x*dx` =


Evaluate the following.

`int x^3 e^(x^2)`dx


Evaluate the following.

`int "e"^"x" "x - 1"/("x + 1")^3` dx


Evaluate the following.

`int (log "x")/(1 + log "x")^2` dx


Choose the correct alternative from the following.

`int (1 - "x")^(-2) "dx"` = 


Choose the correct alternative from the following.

`int (("x"^3 + 3"x"^2 + 3"x" + 1))/("x + 1")^5  "dx"` = 


Evaluate: `int "dx"/(25"x" - "x"(log "x")^2)`


`int (sinx)/(1 + sin x)  "d"x`


`int sin4x cos3x  "d"x`


`int (x^2 + x - 6)/((x - 2)(x - 1))  "d"x` = x + ______ + c


`int log x * [log ("e"x)]^-2` dx = ?


`int "e"^x [x (log x)^2 + 2 log x] "dx"` = ______.


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


Evaluate: `int_0^(pi/4) (dx)/(1 + tanx)`


Find: `int e^x.sin2xdx`


Solve: `int sqrt(4x^2 + 5)dx`


If `int(x + (cos^-1 3x)^2)/sqrt(1 - 9x^2)dx = 1/α(sqrt(1 - 9x^2) + (cos^-1 3x)^β) + C`, where C is constant of integration , then (α + 3β) is equal to ______.


Evaluate :

`int(4x - 6)/(x^2 - 3x + 5)^(3/2)  dx`


Evaluate: 

`int(1+logx)/(x(3+logx)(2+3logx))  dx`


Solve the differential equation (x2 + y2) dx - 2xy dy = 0 by completing the following activity.

Solution: (x2 + y2) dx - 2xy dy = 0

∴ `dy/dx=(x^2+y^2)/(2xy)`                      ...(1)

Puty = vx

∴ `dy/dx=square`

∴ equation (1) becomes

`x(dv)/dx = square`

∴ `square  dv = dx/x`

On integrating, we get

`int(2v)/(1-v^2) dv =intdx/x`

∴ `-log|1-v^2|=log|x|+c_1`

∴ `log|x| + log|1-v^2|=logc       ...["where" - c_1 = log c]`

∴ x(1 - v2) = c

By putting the value of v, the general solution of the D.E. is `square`= cx


The integrating factor of `ylogy.dx/dy+x-logy=0` is ______.


`int logx  dx = x(1+logx)+c`


Evaluate `int(1 + x + (x^2)/(2!))dx`


Solve the following

`int_0^1 e^(x^2) x^3 dx`


Evaluate:

`inte^x sinx  dx`


If f′(x) = 4x3 − 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate:

`int x^2 cos x  dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×