English

∫e4x-3dx = ______ + c

Advertisements
Advertisements

Question

`int"e"^(4x - 3) "d"x` = ______ + c

Fill in the Blanks
Advertisements

Solution

`int"e"^(4x - 3) "d"x` = `bbunderline(1/4e^(4x-3)` + c

shaalaa.com
  Is there an error in this question or solution?
Chapter 1.5: Integration - Q.2

RELATED QUESTIONS

Prove that:

`int sqrt(x^2 - a^2)dx = x/2sqrt(x^2 - a^2) - a^2/2log|x + sqrt(x^2 - a^2)| + c`


Integrate the function in x sin 3x.


Integrate the function in x log 2x.


Integrate the function in x cos-1 x.


Integrate the function in `e^x (1/x - 1/x^2)`.


Integrate the function in e2x sin x.


`int e^x sec x (1 +   tan x) dx` equals:


Evaluate the following : `int (t.sin^-1 t)/sqrt(1 - t^2).dt`


Evaluate the following : `int cos sqrt(x).dx`


Integrate the following functions w.r.t. x : `(x + 1) sqrt(2x^2 + 3)`


Integrate the following functions w.r.t. x : `sqrt(2x^2 + 3x + 4)`


Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`


Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =


Integrate the following with respect to the respective variable : `(sin^6θ + cos^6θ)/(sin^2θ*cos^2θ)`


Evaluate the following.

∫ x log x dx


Evaluate the following.

`int "e"^"x" "x"/("x + 1")^2` dx


Evaluate:

∫ (log x)2 dx


`int (sinx)/(1 + sin x)  "d"x`


`int ("e"^xlog(sin"e"^x))/(tan"e"^x)  "d"x`


Evaluate the following:

`int (sin^-1 x)/((1 - x)^(3/2)) "d"x`


Evaluate the following:

`int_0^pi x log sin x "d"x`


`int "dx"/(sin(x - "a")sin(x - "b"))` is equal to ______.


`int1/sqrt(x^2 - a^2) dx` = ______


Solution of the equation `xdy/dx=y log y` is ______


The integrating factor of `ylogy.dx/dy+x-logy=0` is ______.


Prove that `int sqrt(x^2 - a^2)dx = x/2 sqrt(x^2 - a^2) - a^2/2 log(x + sqrt(x^2 - a^2)) + c`


The value of `int e^x((1 + sinx)/(1 + cosx))dx` is ______.


Evaluate the following.

`intx^3e^(x^2) dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)


Evaluate the following.

`intx^3 e^(x^2)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×