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Fill in the Blank. xx∫5(x6+1)x2+1 dx = x4 + ______ x3 + 5x + c

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प्रश्न

Fill in the Blank.

`int (5("x"^6 + 1))/("x"^2 + 1)` dx = x4 + ______ x3 + 5x + c

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उत्तर

`int (5("x"^6 + 1))/("x"^2 + 1)` dx = x5 + `underline((-5)/3)` x3 + 5x + c

Explanation:

`"I" = int (5(x^6 + 1))/(x^2 + 1) "dx"`

`"I" = 5 int ((x^2)^3 + (1)^3)/("x"^2 + 1) "dx"`

`"I" = 5int((cancel("x"^2 + 1))("x"^4 - "x"^2 + 1))/(cancel("x"^2 + 1)) "dx"   ...[a^3 + b^3 = (a + b)(a^2 - ab + b^2)]`

`"I" = 5 int ("x"^4 - "x"^2 + 1)` dx

`"I" = 5 ("x"^5/5 - "x"^3/3 + "x") + c         ...[int "x"^"n"  "dx" = "x"^("n" + 1)/("n" + 1)]`

`"I" = "x"^5 - 5/3"x"^3 + 5"x"` + c

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अध्याय 5: Integration - MISCELLANEOUS EXERCISE - 5 [पृष्ठ १३८]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 5 Integration
MISCELLANEOUS EXERCISE - 5 | Q II. 1. | पृष्ठ १३८

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