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Methods of Integration> Integration by Substitution

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Estimated time: 6 minutes
Maharashtra State Board: Class 12

Definition: Integration by Substitution

Integration by substitution is a method in which we replace a part of the integral by a new variable to simplify the integration.

Maharashtra State Board: Class 12

Key Points: Standard Substitution

Sr. No. Integrand Form Substitution
i \[\sqrt{\mathrm{a}^2-x^2},\frac{1}{\sqrt{\mathrm{a}^2-x^2}},\mathrm{a}^2-x^2\] x = a sinθ or x = a cosθ
ii \[\sqrt{x^2+\mathrm{a}^2},\frac{1}{\sqrt{x^2+\mathrm{a}^2}},x^2+\mathrm{a}^2\] x = a tanθ
iii \[\sqrt{x^{2}-a^{2}},\frac{1}{\sqrt{x^{2}-a^{2}}},x^{2}-a^{2}\] x = a secθ
iv \[\sqrt{\frac{x}{a+x}},\sqrt{\frac{a+x}{x}},\]\[\sqrt{x(a+x)},\frac{1}{\sqrt{x(a+x)}}\] x = a tan²θ
v \[\sqrt{\frac{x}{a-x}},\sqrt{\frac{a-x}{x}},\]\[\sqrt{x(a-x)},\frac{1}{\sqrt{x(a-x)}}\] x = a sin²θ
vi \[\sqrt{\frac{x}{x-a}},\sqrt{\frac{x-a}{x}},\]\[\sqrt{x(x-\mathrm{a})},\frac{1}{\sqrt{x(x-\mathrm{a})}}\] x = a sec²θ
vii \[\sqrt{\frac{\mathrm{a}-x}{\mathrm{a}+x}},\sqrt{\frac{\mathrm{a}+x}{\mathrm{a}-x}}\] x = a cos 2θ
viii \[\sqrt{\frac{x-\alpha}{\beta-x}},\sqrt{(x-\alpha)(\beta-x)},\]\[(\beta>\alpha)\] x = α cos²θ + β sin²θ

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Shaalaa.com | Indefinite Integration by U Substitution

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Indefinite Integration by U Substitution [00:29:56]
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