हिंदी

∫1x2-a2 dx = ______ + c

Advertisements
Advertisements

प्रश्न

`int 1/(x^2 - "a"^2)  "d"x` = ______ + c

रिक्त स्थान भरें
Advertisements

उत्तर

`1/(2"a") log |(x - "a")/(x + "a")|` 

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1.5: Integration - Q.2

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Integrate the function in x tan-1 x.


Integrate the function in `e^x (1 + sin x)/(1+cos x)`.


`int e^x sec x (1 +   tan x) dx` equals:


Find : 

`∫(log x)^2 dx`


Evaluate the following : `int x^2.log x.dx`


Integrate the following functions w.r.t. x:

sin (log x)


Integrate the following functions w.r.t. x : `xsqrt(5 - 4x - x^2)`


Integrate the following functions w.r.t. x : `e^x .(1/x - 1/x^2)`


Integrate the following with respect to the respective variable : `(3 - 2sinx)/(cos^2x)`


Evaluate the following.

`int x^2 *e^(3x)`dx


Evaluate the following.

`int x^3 e^(x^2)`dx


Evaluate the following.

`int e^x (1/x - 1/x^2)`dx


`int ["cosec"(logx)][1 - cot(logx)]  "d"x`


`int (x^2 + x - 6)/((x - 2)(x - 1))  "d"x` = x + ______ + c


`int logx/(1 + logx)^2  "d"x`


`int log x * [log ("e"x)]^-2` dx = ?


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


Find: `int e^x.sin2xdx`


If `int(2e^(5x) + e^(4x) - 4e^(3x) + 4e^(2x) + 2e^x)/((e^(2x) + 4)(e^(2x) - 1)^2)dx = tan^-1(e^x/a) - 1/(b(e^(2x) - 1)) + C`, where C is constant of integration, then value of a + b is equal to ______.


The integral `int x cos^-1 ((1 - x^2)/(1 + x^2))dx (x > 0)` is equal to ______.


Find `int (sin^-1x)/(1 - x^2)^(3//2) dx`.


`int logx  dx = x(1+logx)+c`


Evaluate the following.

`int (x^3)/(sqrt(1 + x^4))dx`


Prove that `int sqrt(x^2 - a^2)dx = x/2 sqrt(x^2 - a^2) - a^2/2 log(x + sqrt(x^2 - a^2)) + c`


Evaluate the following.

`intx^3  e^(x^2) dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)


Evaluate the following.

`intx^3/(sqrt(1 + x^4))dx`


Which expression is the integration-by-parts form for a product \(f(x)g(x)\)?


Repeated parts may be needed for which pair of integrals?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×