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प्रश्न
The slope of a tangent to the curve y = 3x2 – x + 1 at (1, 3) is ______.
विकल्प
5
– 5
`(-1)/5`
`1/5`
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उत्तर
The slope of a tangent to the curve y = 3x2 – x + 1 at (1, 3) is 5.
Explanation:
y = 3x2 – x + 1
∴ Slope of a tangent = `(dy)/(dx)` = 6x – 1
∴ `((dy)/(dx))_((1, 3)` = 6 × 1 – 1 = 5
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