हिंदी

Find the Area Bounded by the Curve X2 = 4y and the Line X = 4y – 2

Advertisements
Advertisements

प्रश्न

Find the area bounded by the curve x2 = 4y and the line x = 4– 2

Advertisements

उत्तर

The area bounded by the curve, x2 = 4y, and line, x = 4– 2, is represented by the shaded area OBAO.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Application of Integrals - Exercise 8.1 [पृष्ठ ३६६]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 8 Application of Integrals
Exercise 8.1 | Q 10 | पृष्ठ ३६६

वीडियो ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्न

Using integration find the area of the triangle formed by positive x-axis and tangent and normal of the circle

`x^2+y^2=4 at (1, sqrt3)`


Find the area of the region bounded by x2 = 4yy = 2, y = 4 and the y-axis in the first quadrant.


Find the area of the region bounded by the ellipse  `x^2/16 + y^2/9 = 1.`


Find the area of the region bounded by the ellipse `x^2/4 + y^2/9 = 1.`


Find the area of the region in the first quadrant enclosed by x-axis, line x = `sqrt3` y and the circle x2 + y2 = 4.


Find the area of the smaller part of the circle x2 + y2 = a2 cut off by the line  `x = a/sqrt2`


The area between x = y2 and x = 4 is divided into two equal parts by the line x = a, find the value of a.


Sketch the graph of y = |x + 3| and evaluate `int_(-6)^0 |x + 3|dx`


Find the area of the smaller region bounded by the ellipse `x^2/9 + y^2/4` and the line `x/3 + y/2 = 1`


Using the method of integration, find the area of the triangle ABC, coordinates of whose vertices are A (4 , 1), B (6, 6) and C (8, 4).


Find the area of the smaller region bounded by the ellipse \[\frac{x^2}{9} + \frac{y^2}{4} = 1\] and the line \[\frac{x}{3} + \frac{y}{2} = 1 .\]


Find the area of the region bounded by the parabola y2 = 16x and the line x = 4. 


Draw a rough sketch and find the area bounded by the curve x2 = y and x + y = 2.


Find the area of the region bounded by the following curves, the X-axis and the given lines:

y = x2 + 1, x = 0, x = 3


Find the area of the region bounded by the following curve, the X-axis and the given line:

y = 2 – x2, x = –1, x = 1


Using definite integration, area of the circle x2 + y2 = 49 is _______.


State whether the following is True or False :

The area bounded by the curve x = g (y), Y-axis and bounded between the lines y = c and y = d is given by `int_"c"^"d"x*dy = int_(y = "c")^(y = "d") "g"(y)*dy` 


Choose the correct alternative:

Area of the region bounded by the curve y = x3, x = 1, x = 4 and the X-axis is ______


The area of the region bounded by the curve y2 = x and the Y axis in the first quadrant and lines y = 3 and y = 9 is ______


The area of the region x2 = 4y, y = 1 and y = 2 and the Y axis lying in the first quadrant is ______


The area of the region bounded by y2 = 25x, x = 1 and x = 2 the X axis is ______


Find area of the region bounded by 2x + 4y = 10, y = 2 and y = 4 and the Y-axis lying in the first quadrant


Find area of the region bounded by the parabola x2 = 36y, y = 1 and y = 4, and the positive Y-axis


Find the area of the circle x2 + y2 = 16


If `int_0^(pi/2) log (cos x) "dx" = - pi/2 log 2,` then `int_0^(pi/2) log (cosec x)`dx = ?


The area of the region bounded by the curve y = 4x3 − 6x2 + 4x + 1 and the lines x = 1, x = 5 and X-axis is ____________.


The area bounded by y = `27/x^3`, X-axis and the ordinates x = 1, x = 3 is ______


`int_0^log5 (e^xsqrt(e^x - 1))/(e^x + 3)` dx = ______ 


Area enclosed between the curve y2(4 - x) = x3 and line x = 4 above X-axis is ______.


Which equation below represents a parabola that opens upward with a vertex at (0, – 5)?


The equation of curve through the point (1, 0), if the slope of the tangent to t e curve at any point (x, y) is `(y - 1)/(x^2 + x)`, is


If a2 + b2 + c2 = – 2 and f(x) = `|(1 + a^2x, (1 + b^2)x, (1 + c^2)x),((1 + a^2)x, 1 + b^2x, (1 + c^2)x),((1 + a^2)x, (1 + b^2)x, 1 + c^2x)|` then f(x) is a polynomial of degree


The area of the region bounded by the curve y = x2, x = 0, x = 3, and the X-axis is ______.


Area bounded by y = sec2x, x = `π/6`, x = `π/3` and x-axis is ______.


The area bounded by the curve, y = –x, X-axis, x = 1 and x = 4 is ______.


The area enclosed by the parabola x2 = 4y and its latus rectum is `8/(6m)` sq units. Then the value of m is ______.


Find the area of the region lying in the first quadrant and bounded by y = 4x2, x = 0,y = 2 and y = 4.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×