हिंदी

Fill in the blank : The area of the region bounded by the curve x2 = y, the X-axis and the lines x = 3 and x = 9 is _______.

Advertisements
Advertisements

प्रश्न

Fill in the blank :

The area of the region bounded by the curve x2 = y, the X-axis and the lines x = 3 and x = 9 is _______.

रिक्त स्थान भरें
Advertisements

उत्तर

Required area = `int_3^9 y*dx`

= `int_3^9 x^2*dx`

= `[x^3/3]_3^9`

= `(1)/(3)(9^3 - 3^3)`

= `(1)/(3)(729 - 27)`

= `(702)/(3)`
= 234 sq. units.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Applications of Definite Integration - Miscellaneous Exercise 7 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 7 Applications of Definite Integration
Miscellaneous Exercise 7 | Q 2.4 | पृष्ठ १५८

संबंधित प्रश्न

Find the area of the region bounded by the ellipse  `x^2/16 + y^2/9 = 1.`


Find the area of the region enclosed by the parabola x2 = y, the line y = x + 2 and x-axis


Using the method of integration find the area of the triangle ABC, coordinates of whose vertices are A(2, 0), B (4, 5) and C (6, 3).


Using the method of integration, find the area of the triangle ABC, coordinates of whose vertices are A (4 , 1), B (6, 6) and C (8, 4).


Find the area enclosed between the parabola 4y = 3x2 and the straight line 3x - 2y + 12 = 0.


Find the area of the region bounded by the parabola y2 = 16x and the line x = 4. 


Find the area of the region. 

{(x,y) : 0 ≤ y ≤ x, 0 ≤ y ≤ x + 2 ,-1 ≤ x ≤ 3} .


Find the area of the region bounded by the following curves, the X-axis and the given lines:

y = x2 + 1, x = 0, x = 3


Find the area of the region bounded by the parabola y2 = 4x and the line x = 3.


Choose the correct alternative :

Area of the region bounded by the curve x2 = y, the X-axis and the lines x = 1 and x = 3 is _______.


If the curve, under consideration, is below the X-axis, then the area bounded by curve, X-axis and lines x = a, x = b is positive.


Solve the following:

Find the area of the region bounded by the curve x2 = 25y, y = 1, y = 4 and the Y-axis.


Choose the correct alternative:

Area of the region bounded by y2 = 16x, x = 1 and x = 4 and the X axis, lying in the first quadrant is ______


State whether the following statement is True or False:

The area of portion lying below the X axis is negative


The area bounded by the parabola x2 = 9y and the lines y = 4 and y = 9 in the first quadrant is ______


Find the area of the region bounded by the curve y = `sqrt(9 - x^2)`, X-axis and lines x = 0 and x = 3


Find the area of the region bounded by the curve y = `sqrt(36 - x^2)`, the X-axis lying in the first quadrant and the lines x = 0 and x = 6


Find the area of the circle x2 + y2 = 16


If `int_0^(pi/2) log (cos x) "dx" = - pi/2 log 2,` then `int_0^(pi/2) log (cosec x)`dx = ?


Area bounded by the curve xy = 4, X-axis between x = 1, x = 5 is ______.


Area enclosed between the curve y2(4 - x) = x3 and line x = 4 above X-axis is ______.


Equation of a common tangent to the circle, x2 + y2 – 6x = 0 and the parabola, y2 = 4x, is:


The area of the region bounded by the curve y = x2, x = 0, x = 3, and the X-axis is ______.


Area of the region bounded by y= x4, x = 1, x = 5 and the X-axis is ______.


Area in first quadrant bounded by y = 4x2, x = 0, y = 1 and y = 4 is ______.


Area bounded by y = sec2x, x = `π/6`, x = `π/3` and x-axis is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×