मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Fill in the blank : The area of the region bounded by the curve x2 = y, the X-axis and the lines x = 3 and x = 9 is _______. - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Fill in the blank :

The area of the region bounded by the curve x2 = y, the X-axis and the lines x = 3 and x = 9 is _______.

रिकाम्या जागा भरा
Advertisements

उत्तर

Required area = `int_3^9 y*dx`

= `int_3^9 x^2*dx`

= `[x^3/3]_3^9`

= `(1)/(3)(9^3 - 3^3)`

= `(1)/(3)(729 - 27)`

= `(702)/(3)`
= 234 sq. units.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Applications of Definite Integration - Miscellaneous Exercise 7 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 7 Applications of Definite Integration
Miscellaneous Exercise 7 | Q 2.4 | पृष्ठ १५८

संबंधित प्रश्‍न

Find the area of the region in the first quadrant enclosed by the x-axis, the line y = x and the circle x2 + y2 = 32.


Find the area of the region bounded by y2 = 9x, x = 2, x = 4 and the x-axis in the first quadrant.


Find the area of the smaller part of the circle x2 + y2 = a2 cut off by the line  `x = a/sqrt2`


Find the area of the region {(x, y) : y2 ≤ 4x, 4x2 + 4y2 ≤ 9}


Using integration, find the area of the region {(x, y) : x2 + y2 ≤ 1 ≤ x + y}.


Find the area of the smaller region bounded by the ellipse \[\frac{x^2}{9} + \frac{y^2}{4} = 1\] and the line \[\frac{x}{3} + \frac{y}{2} = 1 .\]


Find the area of the region. 

{(x,y) : 0 ≤ y ≤ x, 0 ≤ y ≤ x + 2 ,-1 ≤ x ≤ 3} .


Using integration find the area of the triangle formed by negative x-axis and tangent and normal to the circle `"x"^2 + "y"^2 = 9  "at" (-1,2sqrt2)`.


Find the area of the region bounded by the parabola y2 = 4x and the line x = 3.


Choose the correct alternative :

Area of the region bounded by the curve x2 = y, the X-axis and the lines x = 1 and x = 3 is _______.


The area of the region bounded by y2 = 4x, the X-axis and the lines x = 1 and x = 4 is _______.


Choose the correct alternative :

Area of the region bounded by y = x4, x = 1, x = 5 and the X-axis is _____.


The area of the region bounded by y2 = 4x, the X-axis and the lines x = 1 and x = 4 is _______.


Solve the following :

Find the area of the region bounded by the curve y = x2 and the line y = 10.


Find the area of the region bounded by y = x2, the X-axis and x = 1, x = 4.


Choose the correct alternative:

Area of the region bounded by the curve x2 = 8y, the positive Y-axis lying in the first quadrant and the lines y = 4 and y = 9 is ______


The area of the shaded region bounded by two curves y = f(x), and y = g(x) and X-axis is `int_"a"^"b" "f"(x) "d"x + int_"a"^"b" "g"(x)  "d"x`


The area of the region lying in the first quadrant and bounded by the curve y = 4x2, and the lines y = 2 and y = 4 is ______


The area of the region bounded by the curve y2 = x and the Y axis in the first quadrant and lines y = 3 and y = 9 is ______


The area of the region x2 = 4y, y = 1 and y = 2 and the Y axis lying in the first quadrant is ______


Find the area of the region bounded by the curve 4y = 7x + 9, the X-axis and the lines x = 2 and x = 8


If `int_0^(pi/2) log (cos x) "dx" = - pi/2 log 2,` then `int_0^(pi/2) log (cosec x)`dx = ?


The area of the region bounded by the curve y = 4x3 − 6x2 + 4x + 1 and the lines x = 1, x = 5 and X-axis is ____________.


The area bounded by y = `27/x^3`, X-axis and the ordinates x = 1, x = 3 is ______


The area enclosed between the curve y = loge(x + e) and the coordinate axes is ______.


`int "e"^x ((sqrt(1 - x^2) * sin^-1 x + 1)/sqrt(1 - x^2))`dx = ________.


The equation of curve through the point (1, 0), if the slope of the tangent to t e curve at any point (x, y) is `(y - 1)/(x^2 + x)`, is


Area bounded by the curves y = `"e"^(x^2)`, the x-axis and the lines x = 1, x = 2 is given to be α square units. If the area bounded by the curve y = `sqrt(ℓ "n"x)`, the x-axis and the lines x = e and x = e4 is expressed as (pe4 – qe – α), (where p and q are positive integers), then (p + q) is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×