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प्रश्न
Integrate the function in `e^x (1/x - 1/x^2)`.
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उत्तर
Let `I = inte^x (1/x - 1/x^2) dx`
`= int e^x {1/x + [d/dx (1/x)]} dx`
`= e^x xx 1/x + C = e^x/x + C` `...[∵ int e^x (f (x)+ f' (x)) dx = e^x f (x) + C]`
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