मराठी

Integrate the function in ex1+sinx1+cosx.

Advertisements
Advertisements

प्रश्न

Integrate the function in `e^x (1 + sin x)/(1+cos x)`.

बेरीज
Advertisements

उत्तर

Let `I = int (e^x(1 + sin x))/(1 + cos x)  dx`

`I = int e^x [(1 + sin  x/2 cos  x/2)/(2 cos^2  x/2)]  dx`

`= inte^x [1/2 sec^2  x/2 + tan  x/2]  dx`

`I = inte^x [tan  x/2 + 1/2 sec^2  x/2]  dx`

`= e^x {tan  x/2 + [d/dx(tan  x/2)]}`

`= e^x * tan (x/2) + C`       `...[∵ int e^x (f(x) + f' (x)) dx = e^x f (x) + C]`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Integrals - Exercise 7.6 [पृष्ठ ३२८]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.6 | Q 18 | पृष्ठ ३२८

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Prove that: `int sqrt(a^2 - x^2) * dx = x/2 * sqrt(a^2 - x^2) + a^2/2 * sin^-1(x/a) + c`


If `int_(-pi/2)^(pi/2)sin^4x/(sin^4x+cos^4x)dx`, then the value of I is:

(A) 0

(B) π

(C) π/2

(D) π/4


`int1/xlogxdx=...............`

(A)log(log x)+ c

(B) 1/2 (logx )2+c

(C) 2log x + c

(D) log x + c


Evaluate `int_0^(pi)e^2x.sin(pi/4+x)dx`


Integrate the function in xlog x.


Integrate the function in `((x- 3)e^x)/(x - 1)^3`.


Evaluate the following : `int x^2tan^-1x.dx`


Evaluate the following:

`int sec^3x.dx`


Evaluate the following : `int x^3.logx.dx`


Evaluate the following : `int sin θ.log (cos θ).dθ`


Evaluate the following:

`int x.sin 2x. cos 5x.dx`


Evaluate the following : `int cos(root(3)(x)).dx`


Integrate the following functions w.r.t. x : `sec^2x.sqrt(tan^2x + tan x - 7)`


Integrate the following functions w.r.t. x : [2 + cot x – cosec2x]e 


Integrate the following functions w.r.t. x : `e^x/x [x (logx)^2 + 2 (logx)]`


Integrate the following functions w.r.t. x : cosec (log x)[1 – cot (log x)] 


Choose the correct options from the given alternatives :

`int (log (3x))/(xlog (9x))*dx` =


Integrate the following with respect to the respective variable : cos 3x cos 2x cos x


Integrate the following w.r.t.x : cot–1 (1 – x + x2)


Integrate the following w.r.t.x : `sqrt(x)sec(x^(3/2))*tan(x^(3/2))`


Integrate the following w.r.t.x : e2x sin x cos x


Choose the correct alternative from the following.

`int (1 - "x")^(-2) "dx"` = 


Evaluate: `int ("ae"^("x") + "be"^(-"x"))/("ae"^("x") - "be"^(−"x"))` dx


Evaluate: `int e^x/sqrt(e^(2x) + 4e^x + 13)` dx


Evaluate: `int "dx"/("x"[(log "x")^2 + 4 log "x" - 1])`


Evaluate: `int "dx"/(25"x" - "x"(log "x")^2)`


`int 1/(x^2 - "a"^2)  "d"x` = ______ + c


`int"e"^(4x - 3) "d"x` = ______ + c


Evaluate `int (2x + 1)/((x + 1)(x - 2))  "d"x`


`int "e"^x x/(x + 1)^2  "d"x`


`int_0^"a" sqrt("x"/("a" - "x")) "dx"` = ____________.


`int "e"^x int [(2 - sin 2x)/(1 - cos 2x)]`dx = ______.


Find `int_0^1 x(tan^-1x)  "d"x`


`int e^x [(2 + sin 2x)/(1 + cos 2x)]dx` = ______.


`intsqrt(1+x)  dx` = ______


`inte^(xloga).e^x dx` is ______


`int(f'(x))/sqrt(f(x)) dx = 2sqrt(f(x))+c`


Evaluate:

`int((1 + sinx)/(1 + cosx))e^x dx`


Prove that `int sqrt(x^2 - a^2)dx = x/2 sqrt(x^2 - a^2) - a^2/2 log(x + sqrt(x^2 - a^2)) + c`


Evaluate the following. 

`int x sqrt(1 + x^2)  dx`  


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×