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Integrate the following functions w.r.t. x : (x+1)2x2+3

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प्रश्न

Integrate the following functions w.r.t. x : `(x + 1) sqrt(2x^2 + 3)`

बेरीज
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उत्तर

Let I = `int (x + 1)sqrt(2x^2 + 3)`

Let x + 1 = `"A"[d/dx (2x^2 + 3)] + "B"`

= A (4x) + B
= 4Ax + B
Comparing the coefficients of and constant on both sides, we get
4A = 1, B = 1

∴ A = `(1)/(4), "B"` = 1

∴ x + 1 = `(1)/(4)(4x) + 1`

∴ I = `int [1/4 (4x) + 1]sqrt(2x^2 + 3).dx`

= `(1)/(4) int 4x sqrt(2x^2 + 3).dx + int sqrt(2x^2 + 3).dx`.

= I1 + I2

In I1 = put 2x2 + 3 = t
∴ 4x.dx = dt

∴ I1 = `(1)/(4) int t^(12).dt`

= `(1)/(4)(t^(3/2)/(3/2)) + c_1`

= `(1)/(6)(2x^2 + 3)^(3/2) + c_1`

I2 = `int sqrt(2x^2 + 3).dx`

= `sqrt(2) int sqrt(x^2 + 3/2).dx`

= `sqrt(2)[x/2sqrt(x^2 + 3/2) + ((3/2))/(2)log|x + sqrt(x^2 + 3/2)|] + c_2`

= `sqrt(2)[x/2sqrt(x^2 + 3/2) + (3)/(4)log|x + sqrt(x^2 + 3/2)|] + c_2`

∴ I = `(1)/(6)(2x^2 + 3)^(3/2) + sqrt(2)[x/2 sqrt(x^2 + 3/2) + (3)/(4) log|x + sqrt(x^2 + 3/2)|] + c`, where c = c1 + c2.

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पाठ 3: Indefinite Integration - Exercise 3.3 [पृष्ठ १३८]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.3 | Q 2.08 | पृष्ठ १३८

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