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प्रश्न
`int 1/sqrt(2x^2 - 5) "d"x`
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उत्तर
Let I = `int 1/sqrt(2x^2 - 5) "d"x`
= `int 1/sqrt(2(x^2 - 5/2)) "d"x`
= `1/sqrt(2) int 1/sqrt(x^2 - (sqrt(5)/sqrt(2))^2) "d"x`
= `1/sqrt(2) log|x + sqrt(x^2 - (sqrt(5)/sqrt(2))^2)| + "c"`
∴ I = `1/sqrt(2) log|x + sqrt(x^2 - 5/2)| + "c"`
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