English

Integrate the following functions w.r.t. x : log(1+x)(1+x) - Mathematics and Statistics

Advertisements
Advertisements

Question

Integrate the following functions w.r.t. x : `log(1 + x)^((1 + x)`

Sum
Advertisements

Solution

Let I = `int log (1 + x)^((1 + x)).dx`

= `int (1 + x)log(1 + x).dx`

= `int [log(1 + x)] (1 + x).dx`

= `[log(1 + x) int (1 + x).dx - int[d/dt {log(1 + x)} int (1 + x).dx].dx`

= `[log (1 + x)] [(1 + x)^2/2] - int 1/(x + 1).(x + 1)^2/(2).dx`

= `(x + 1)^2/(2).log(1 + x) - (1)/(2) int (x + 1).dx`

= `(x + 1)^2/(2).log (1 + x) - (1)/(2).(x + 1)^2/(2) + c`

= `(x + 1)^2/(2)[log (1 + x) - 1/2] + c`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Exercise 3.3 [Page 138]

APPEARS IN

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Integrate : sec3 x w. r. t. x.


Integrate the function in x log 2x.


Integrate the function in xlog x.


Integrate the function in `e^x (1/x - 1/x^2)`.


Evaluate the following:

`int sec^3x.dx`


Evaluate the following : `int e^(2x).cos 3x.dx`


Integrate the following functions w.r.t. x : `sqrt((x - 3)(7 - x)`


Integrate the following functions w.r.t. x : `sqrt(4^x(4^x + 4))`


Integrate the following functions w.r.t. x : `[x/(x + 1)^2].e^x`


Integrate the following functions w.r.t. x : `e^x/x [x (logx)^2 + 2 (logx)]`


Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`


Integrate the following functions w.r.t. x : `e^(sin^-1x)*[(x + sqrt(1 - x^2))/sqrt(1 - x^2)]`


Choose the correct options from the given alternatives :

`int (1)/(x + x^5)*dx` = f(x) + c, then `int x^4/(x + x^5)*dx` =


Integrate the following w.r.t.x : `log (1 + cosx) - xtan(x/2)`


Integrate the following w.r.t.x : log (log x)+(log x)–2 


Integrate the following w.r.t.x : sec4x cosec2x


Solve the following differential equation.

(x2 − yx2 ) dy + (y2 + xy2) dx = 0


Evaluate the following.

`int (log "x")/(1 + log "x")^2` dx


Choose the correct alternative from the following.

`int (("e"^"2x" + "e"^"-2x")/"e"^"x") "dx"` = 


Evaluate: `int ("ae"^("x") + "be"^(-"x"))/("ae"^("x") - "be"^(−"x"))` dx


`int (sinx)/(1 + sin x)  "d"x`


`int (cos2x)/(sin^2x cos^2x)  "d"x`


Choose the correct alternative:

`int ("d"x)/((x - 8)(x + 7))` =


`int (x^2 + x - 6)/((x - 2)(x - 1))  "d"x` = x + ______ + c


Evaluate `int 1/(x log x)  "d"x`


`int "e"^x x/(x + 1)^2  "d"x`


`int_0^"a" sqrt("x"/("a" - "x")) "dx"` = ____________.


`int "dx"/(sin(x - "a")sin(x - "b"))` is equal to ______.


The value of `int_(- pi/2)^(pi/2) (x^3 + x cos x + tan^5x + 1)  dx` is


`int 1/sqrt(x^2 - 9) dx` = ______.


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


Evaluate: `int_0^(pi/4) (dx)/(1 + tanx)`


Find: `int e^x.sin2xdx`


`int(logx)^2dx` equals ______.


`int_0^1 x tan^-1 x  dx` = ______.


`int((4e^x - 25)/(2e^x - 5))dx = Ax + B log(2e^x - 5) + c`, then ______.


Find `int (sin^-1x)/(1 - x^2)^(3//2) dx`.


`int(3x^2)/sqrt(1+x^3) dx = sqrt(1+x^3)+c`


`int(xe^x)/((1+x)^2)  dx` = ______


Evaluate `int(1 + x + (x^2)/(2!))dx`


Evaluate:

`inte^x sinx  dx`


`int (sin^-1 sqrt(x) + cos^-1 sqrt(x))dx` = ______.


The value of `int e^x((1 + sinx)/(1 + cosx))dx` is ______.


Evaluate:

`int (sin(x - a))/(sin(x + a))dx`


Evaluate the following.

`intx^3  e^(x^2) dx`


Evaluate the following:

`intx^3e^(x^2)dx` 


Evaluate `int (1 + x + x^2/(2!))dx`


Evaluate `int(1 + x + x^2/(2!))dx`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×